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dexar [7]
4 years ago
15

2.30% of what number is 15

Mathematics
1 answer:
avanturin [10]4 years ago
3 0

The answer is 652.17

Step-by-step explanation:

First, You want to convert the percent to a decimal

2.30% =.023

Then take your value of 15 and divide it by that decimal

15/.023

and that will give you 652.17

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Step-by-step explanation:

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3 years ago
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Data on IQ for 33 first graders are given as follows: 82, 96, 99, 102, 103, 103, 106, 107, 108, 108, 108, 108, 109, 110, 110, 11
Dahasolnce [82]

Answer:

\bar X = \frac{\sum_{i=1}^n x_i}{n}

Where n represent the sample size, on this case n =33. If we use this formula we got:

\bar X = 113.727

And for this case we know that is the best estimator since is an unbiased estimator for the true population mean since we have this:

E(\bar X) = E(\frac{\sum_{i=1}^n x_i}{n})= \frac{1}{n} \sum_{i=1}^n E(X_i) = \frac{n\mu}{n} = \mu

Step-by-step explanation:

For this case we have the following values given:

82, 96, 99, 102, 103, 103, 106, 107, 108, 108, 108, 108, 109, 110, 110, 111, 113, 113, 113, 113, 115, 115, 118, 118, 119, 121, 122, 122, 127, 132, 136, 140, 146

And we want to estimate the mean value of IQ for the conceptual population.

For this case we can use as estimator for the population mean the sample mean. We know that the sample mean is given by this formula:

\bar X = \frac{\sum_{i=1}^n x_i}{n}

Where n represent the sample size, on this case n =33. If we use this formula we got:

\bar X = 113.727

And for this case we know that is the best estimator since is an unbiased estimator for the true population mean since we have this:

E(\bar X) = E(\frac{\sum_{i=1}^n x_i}{n})= \frac{1}{n} \sum_{i=1}^n E(X_i) = \frac{n\mu}{n} = \mu

5 0
3 years ago
Omar walked across the room, a distance of 6.75 yards, in 5.3 seconds. Write a unit rate to describe how quickly Omar walked in
adoni [48]

Answer:

1.273584906 yds / second

Step-by-step explanation:

Take the number of yards and divide by the number of seconds

6.75 yds / 5.3 seconds

1.273584906 yds / second

6 0
3 years ago
Read 2 more answers
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