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belka [17]
3 years ago
9

(01.07)

Mathematics
1 answer:
inna [77]3 years ago
4 0
Answer: Associative Property of Addition

We basically have 2+x+y on each side. The difference is the use of parenthesis in different places. With addition, we can add in any order we want and that includes grouping terms as well. For example
(2+3)+5 = (5)+5 = 5+5 = 10
2+(3+5) = 2+(8) = 2+8 = 10

So that's why in general (2+x)+y = 2+(x+y) is true for all real numbers x and y.
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You’re walking down the hall and you overhear someone talking about you behind your back. What would you do and why?
Alina [70]

Answer: Go up and confront them because i hate when people do that!

Step-by-step explanation:

7 0
3 years ago
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A person can pay $15 for a membership to the history museum and then go to the museum
Finger [1]

Answer: the person would have to visit a total of twelve times for it to add up to $48

Step-by-step explanation:

48-15=33

then divide the 33 by 3 and you get 11 plus the 15 dollar membership and visit will get u 12 visits for $48.

7 0
3 years ago
X squared = −169. A= undefined B= 13 C= ±13 D= −13
mash [69]

Answer:

A.   Undefined.

Step-by-step explanation:

There is no real square root of a negative number.

7 0
3 years ago
Find the absolute maximum and absolute minimum values of f on the given interval. f(t) = 9t + 9 cot(t/2), [π/4, 7π/4]
agasfer [191]

Answer:

the absolute maximum value is 89.96 and

the absolute minimum value is 23.173

Step-by-step explanation:

Here we have cotangent given by the following relation;

cot \theta =\frac{1 }{tan \theta} so that the expression becomes

f(t) = 9t +9/tan(t/2)

Therefore, to look for the point of local extremum, we differentiate, the expression as follows;

f'(t) = \frac{\mathrm{d} \left (9t +9/tan(t/2)  \right )}{\mathrm{d} t} = \frac{9\cdot sin^{2}(t)-\left (9\cdot cos^{2}(t)-18\cdot cos(t)+9  \right )}{2\cdot cos^{2}(t)-4\cdot cos(t)+2}

Equating to 0 and solving gives

\frac{9\cdot sin^{2}(t)-\left (9\cdot cos^{2}(t)-18\cdot cos(t)+9  \right )}{2\cdot cos^{2}(t)-4\cdot cos(t)+2} = 0

t=\frac{4\pi n_1 +\pi }{2} ; t = \frac{4\pi n_2 -\pi }{2}

Where n_i is an integer hence when n₁ = 0 and n₂ = 1 we have t = π/4 and t = 3π/2 respectively

Or we have by chain rule

f'(t) = 9 -(9/2)csc²(t/2)

Equating to zero gives

9 -(9/2)csc²(t/2) = 0

csc²(t/2)  = 2

csc(t/2) = ±√2

The solutions are, in quadrant 1, t/2 = π/4 such that t = π/2 or

in quadrant 2 we have t/2 = π - π/4 so that t = 3π/2

We then evaluate between the given closed interval to find the absolute maximum and absolute minimum as follows;

f(x) for x = π/4, π/2, 3π/2, 7π/2

f(π/4) = 9·π/4 +9/tan(π/8) = 28.7965

f(π/2) = 9·π/2 +9/tan(π/4) = 23.137

f(3π/2) = 9·3π/2 +9/tan(3·π/4) = 33.412

f(7π/2) = 9·7π/2 +9/tan(7π/4) = 89.96

Therefore the absolute maximum value = 89.96 and

the absolute minimum value = 23.173.

7 0
3 years ago
Arc CD is One-fourth of the circumference of a circle. What is the radian measure of the central angle?
GalinKa [24]

Answer:

B--StartFraction pi Over 2 EndFraction radians

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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