Answer:
a. P=0.35
b. P=0.12
c. P=0.49
d. Cost: more than $249 per night.
Step-by-step explanation:
We assume a normal distribution with mean $204 and s.d of $55.
To calculate the probability we calculate the z-value for each case
a. What is the probability that a hotel room costs $225 or more
b. What is the probability that a hotel room costs less than $140
c. What is the probability that a hotel room costs between $200 and $300
d. What is the cost of the most expensive 20% of hotel rooms in New York City?
In this case, we have to estimate z' so thats P(z>z')=0.2. This value is z=0.841.
Then, the value of X should be: