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Law Incorporation [45]
3 years ago
6

Use counters to model problems

Mathematics
1 answer:
Pie3 years ago
5 0
What is the problem exactly
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Convert weeks to days>
madam [21]
What is the question that you're asking?
4 0
4 years ago
Given 4x+6/2=9 prove x=3
Montano1993 [528]

Steps:

Step 1: Simplify both sides of the equation.

4x+3=9

Step 2: Subtract 3 from both sides.

4x+3−3=9−3

4x=6

Step 3: Divide both sides by 4.

4x /4  =  6 /4

Answer: x= 3/2

Please mark brainliest

<em><u>Hope this helps.</u></em>

8 0
3 years ago
Read 2 more answers
This table shows values represented by an exponential function.
Bad White [126]

Answer:

a = 2 , f(2)=9

b = 4 , f(4)=64

And replacing the data into the average rate formula we got:

m = \frac{64-9}{4-2}= 27.5

And then the best answer for this case would be:

C. 27.5

Step-by-step explanation:

For this cae we know that the average rate of change of a function is given by this general expresion:

m = \frac{f(b) -f(a)}{b-a}

For this special case from the info of the table we have:

a = 2 , f(2)=9

b = 4 , f(4)=64

And replacing the data into the average rate formula we got:

m = \frac{64-9}{4-2}= 27.5

And then the best answer for this case would be:

C. 27.5

7 0
4 years ago
(бх -Зу = 6<br> (2x-y=-5
BabaBlast [244]

Answer:

6-

Step-by-step explanation:

Your answer should be written in paragraph/essay format.

Any sources used should be cited at the bottom of your paper.

All answers should show you have learned something from Unit 9.  Material from other units will not be graded for this assignment.

If you are stuck, you can think about the following topics: textile mills, interchangeable parts, the Lowell System, unions, labor reform, steamboats, railroads, coal, the telegraph, and/or new inventions.

3 0
3 years ago
Two similar prisms have heights 4 cm and 10cm what is the ratio of their surface areas
Slav-nsk [51]
Let k be the scale factor relating two similar prisms P_{1} and P_{2}, such that for corresponding parts of prisms P_{1} and P_{2} (for heights, in particular) we have k= \frac{height\  of \ P_{1} }{height \ of\  P_{2} }. In our case k= \frac{4}{10} = \frac{2}{5}.
For surfaces area we have \frac{Surface \ area \ of \  P_{1} }{Surface \ area \ of \  P_{2}} = k^{2} =( \frac{2}{5} )^{2}= \frac{4}{25}.
So, the right answer is 4:25 (choice B)



4 0
4 years ago
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