Answer:
c
Step-by-step explanation:
1/(1/2)
2
y=2
Q + d = 16....q = 16 - d
0.25q + 0.10d = 3.10
0.25(16 - d) + 0.10d = 3.10
4 - 0.25d + 0.10d = 3.10
-0.25d + 0.10d = 3.10 - 4
-0.15d = -0.90
d = -0.90/-0.15
d = 6...dimes
q + d = 16
q + 6 = 16
q = 16 - 6
q = 10...quarters
so there are (10 - 6) = 4 more quarters then dimes
Step-by-step explanation:
The Angle Addition Postulate de fusteer Key. Date ... 99° and MZLMF = 36º. Find m2LMN. 6) Find mZWDC if IZEDC = 145° and mZEDW= 61°. N of w. C ... 11) mZHGF = 16x + 4, m EGF = 110°,. 12) mZVUT = 175° ... a H, 16X+4=110 + 3x +11
Answer:
Option (B)
Step-by-step explanation:
Let the weight of one container = x pounds
Therefore, weight of 5 containers = 5x pounds
Weight of the platform = 30 pounds
Total weight of the platform and containers = (5x + 30) pounds
If the maximum weight that can be lifted by the cable = 780 pounds
Inequality representing this situation will be,
(5x + 30) < 780
5x < 780 - 30
5x < 750
x < 150
Therefore, Option (B) is the answer.
