Find two numbers with a sum of 20 and a difference of 14
Make two equations
X+Y=20
X-Y=14
Now add x since y cancels out and add 20+14 To end up with
2x=34
Now divide 2 both sides to get x alone
2x/2=34/2
X=17
Now substitute x answer to first equation and solve for y
17+y=20
Subtract 17 both sides
Y= 3
Your two numbers are
3 and 17
A : 10000 J
B: 625 J
C: 2500 J
Step-by-step explanation:
Step 1:
We know that ,
Kinetic Energy is given by ((1/2) × m × V²) J
where m = Mass of substance
V = Velocity
Step 2:
In first case, m= 50 kg, V=20 m/s
Kinetic energy = 0.5 × 50 × 20 ×20
= 10000 J
In second case, m= 50 kg, V=20 m/s
Kinetic energy = 0.5 × 50 × 5 ×5
= 625 J
In Third case, m= 50 kg, V=10 m/s
Kinetic energy = 0.5 × 50 × 10 ×10
= 2500 J
First replace x with -2 in the g(x) equation and solve:
G(x) = x + 4 = -2 + 4 = 2
Now replace x in the f(x) equation with the solution of g(x).
F(x) = 1-3(2) = 1-6 = -5
Fg(-2) = -5
X-intercept is when y=0;
4x-3(0)=12.3
4x=12.3
x=12.3/4
x=3.075 (x-intercept)
y-intercept is when x=0
4(0)-3y=12.3
-3y=12.3
y=12.3/-3
y=-4.1 (y-intercept)
Hope I helped :)
