Answer:
A. ΔT/Δt=(3/55min)*(Tr-To); B. 12°C
Step-by-step explanation:
In order to find the answer let's detect the information.
Object temperature = To = 0°C
Room temperature = Tr = 22°C
Rate of warming = R
Based on the data we can establish that:
The change (Δ) in temperature of the object through time is proportional to the difference between object and room temperatures, so:
ΔT/Δt=R*(To-Tr)
Let's find the rate (R) first:
Because the object change its temperature from 0°C to 6°C in 5 minutes we have:
ΔT/Δt=R*(Tr-To)
(6-0°C)/5min=R*(22°C-0°C)
6/(5*22min)=R
3/55min=R
So the general equation is:
ΔT/Δt=(3/55min)*(Tr-To)
Now, let's find the temperature after 10 minutes.
ΔT/Δt=R*(Tr-To)
ΔT/10min=(3/55min)*(22°C-0°C)
ΔT=(3/55min)*(22°C)*10min
ΔT=12°C
In conclusion, after 10 minutes the yoghurt has a temperature of 12°C.
