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Otrada [13]
3 years ago
8

At an amusement park you get five points for each bull’s eye you hit, but you loose 10 points for every miss. After 30 tries, Yo

landa lost 90 points. How many bull’s eyes did she hit?
Mathematics
2 answers:
Kaylis [27]3 years ago
7 0
She hit 21 bull’s eyes.
kramer3 years ago
3 0

Answer:

21

Step-by-step explanation:

14 bull's eyes (or hits) and 16 misses.  

The 14 hits earned her five points each, or a total of 70 points.  

The 16 misses cost ten points each, or a total of 160 points lost.  

14 + 16 = 30  

70 - 160 = -90  

SOLUTION:  

points = 5H - 10M = -90 where H = hits and M = misses  

tries = H + M = 30 therefore  

H = 30 - M  

and 5(30 - M) - 10M = -90  

150 - 5M -10M + 90 = 0  

240 -15M = 0  

15M = 240  

M =16  

H = (30 - M) = 16

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To simplify this decimal you need to convert it to a fraction

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You can leave it as an improper fraction or convert it to a mixed number by dividing 503/100 which will get you 5 3/10.

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a hobby shop has 4 times as many model airplanes as model helicopters. the total number of models is 35. how many model airplane
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Suppose that commercial airplane crashes in a certain country occur at the rate of 2.5 per year. what is the probability that fo
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3 years ago
A train travels at a constant speed of 35 miles per hour how long does it take the train to travel 490 miles
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We have to write a proportion. We put 35 over 60 to show that 35 miles can go in every 60 minutes. Next to it we write another fraction and put 490 over x because we are trying to find how many MINUTES first. we multiply 490 by 60 which is 29400. Now we divide that by 35. we get 840 minutes. Now we convert this into hours by dividing it by 60 because there are 60 minutes in an hour. 840 divided by 60 is 14 hours. The answer is 14 hours.
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In a survey of women in a certain country the mean height was 62.9 inches with a standard deviation of 2.81 inches answer the fo
Natasha2012 [34]

The question is incomplete. The complete question is :

In a survey of women in a certain country ( ages 20-29), the mean height was 62.9 inches with a standard deviation of 2.81 inches.  Answer the following questions about the specified normal distribution.  (a) What height represents the 99th percentile?  (b) What height represents the first quartile?  (Round to two decimal places as needed)

Solution :

Let the random variable X represents the height of women in a country.

Given :

X is normal with mean, μ = 62.9 inches and the standard deviation, σ = 2.81 inches

Let,

$Z=\frac{X - 62.9}{2.81}$ , then Z is a standard normal

a). Let the 99th percentile is = a

The point a is such that,

$P(X

$P \left( Z < \frac{a-62.9}{2.81} \right) = 0.99$

From standard table, we get : P( Z < 2.3263) =0.99

∴ $\frac{(a-62.9)}{281} = 2.3263$

  $a= (2.3263 \times 2.81 ) +62.9$

     = 6.536903 + 62.9

     = 69.436903

     = 69.5 (rounding off)

Therefore, the height represents the 99th percentile = 69.5 inches.

b). Let b = height represents the first quartile.

It is given by :

P( X < b) =0.25

$P \left( Z < \frac{(b-62.9)}{2.81} \right) = 0.25$

From the standard normal table,

P( Z < -0.6745) =0.99

∴ $\frac{(b-62.9)}{2.81}= 0.6745$

$b=(0.6745 \times 2.81) +62.9$

  = 1.895345 + 62.9

   = 64.795345

   = 64.8 (rounding off)

Therefore, the height represents the 1st quartile is 64.8 inches.

8 0
3 years ago
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