Y = t*e^(-t/2)
y' = t' [e^(-t/2)] + t [e^(-t/2)]' = e^(-t/2) + t[e^(-t/2)][-1/2]=
y' = [e^(-t/2)] [1 - t/2] = (1/2)[e^(-t/2)] [2 - t] = - (1/2) [e^-t/2)] [t -2]
Answer:
4 feet wide because to find the perimeter you add all the numbers around
1st one on second row I think
OK, the square root of 250 is 15.811 . . .
but since this can't be expressed as a decimal for your purposes, let's try factoring. Since 250 ends in a zero, only numbers 5 or 0 or those ending in 5 or 0 could be factors.
The square root of 250 can be factored into the square root of 25 and the square root of 10.
The square root of 25 is exactly 5, and the exact square root of 10 is another decimal, so your simplified answer can be expressed as 5 times the square root of 10.
