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3 years ago

Plss help! Asap! will give brainlist!

Mathematics

1 answer:

Alex3 years ago

6 0

Answer:

Step-by-step explanation:

Linear Function= y=3x-2

Non-linear function - y=x^2

A non linear function look like a curve when graphed, It has a variable slope value and The input and output of a non-linear system is not directly related

A linear Function A simple linear equation is of the form: y = mx + c

, A linear equation looks like a straight line when graphed., It has a constant slope value and The output of a linear system is directly proportional to its input.

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Am I correct on #13? ONLY REAL ANSWRS OR YOULL GET REPORTED

drek231 [11]

Answer:

Yeah

Step-by-step explanation:

8 0

3 years ago

a recipe uses 1 1/4 cups of milk to make 10 servings. if the same amount of milk is used for each serving, how many servings can

Anestetic [448]

Answer:

128 servings can be made using 1 gallon of milk.

Step-by-step explanation:

Given that:

$1\frac{1}{4}$ cups of milk make 10 servings

$1\frac{1}{4}$ can also be written as 1.25

Ratio of cups of milk to servings = 1.25 : 10

1 gallon = 16 cups

Let,

x be the number of servings made from 1 gallon

Ratio of cups of milk to servings = 16 : x

This is a direct proportion

1.25 : 10 :: 16 : x

Product of mean = Product of extreme

10*16 = 1.25x

160 = 1.25x

1.25x=160

Dividing both sides by 1.25

$\frac{1.25x}{1.25}=\frac{160}{1.25}\\x=128$

Hence,

128 servings can be made using 1 gallon of milk.

3 0

3 years ago

jillians school is selling tickects for a play. the tickets cost $10.50 for adults and $3.75 for students

Natali5045456 [20]

Answer:

What is the question?

Step-by-step explanation:

We need to know what problem to solve with the information provided.

4 0

3 years ago

This is Matrix for pre calc

gavmur [86]

The given system of equations in augmented matrix form is

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\-6&1&2&4&-12\\1&-3&-3&5&-20\\-2&5&6&0&12\end{array}\right]$

If you need to solve this, first get the matrix in RREF:

Add 2(row 1) to row 2, row 1 to -3(row 3), and 2(row 1) to 3(row 4):

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&11&5&-13&37\\0&19&10&4&-10\end{array}\right]$

Add 11(row 2) to -5(row 3), and 19(row 1) to -5(row 4):

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&153&-823\\0&0&-164&132&-1052\end{array}\right]$

Add 164(row 3) to -91(row 4):

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&153&-823\\0&0&0&13080&-39240\end{array}\right]$

Multiply row 4 by 1/13080:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&153&-823\\0&0&0&1&-3\end{array}\right]$

Add -153(row 4) to row 3:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&0&-364\\0&0&0&1&-3\end{array}\right]$

Multiply row 3 by -1/91:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

Add 6(row 3) and -8(row 4) to row 2:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&0&0&-10\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

Multiply row 2 by 1/5:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&1&0&0&-2\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

Add -2(row 2), 4(row 3), and -2(row 4) to row 1:

$\left[\begin{array}{cccc|c}3&0&0&0&3\\0&1&0&0&-2\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

Multiply row 1 by 1/3:

$\left[\begin{array}{cccc|c}1&0&0&0&1\\0&1&0&0&-2\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

So the solution to this system is $(w,x,y,z)=(1,-2,4,-3)$ .

6 0

3 years ago

you want to put 520 quarters in coin wrappers. you need one wrapper for every $10 in quarters. write an equation you can use to

Lisa [10]

40c=520
This is the proper equation because there are 40 quarters in $10. Thus, if we could only fit $10 worth of quarters in each wrapper, we can only fit 40quarters in each wrapper. C represents the amount of wrappers we will need.

Hope this helps!

6 0

3 years ago