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Rom4ik [11]
3 years ago
9

Rigo and Ian went shopping for soccer cleats and practice uniforms. Rigo spent $451, before taxes, and purchased three uniforms

and one pair oof cleats. Ian spent $757, before taxes, and purchased five uniforms and two pairs of cleats.
Mathematics
1 answer:
yan [13]3 years ago
3 0

Answer:

The price of uniform U= $145

price of each pair of cleats C= $16

Step-by-step explanation:

Let:

The Price of Each Uniform = U

The Price of Each Pair of Cleats = C

Rigo spent $451, before taxes, and purchased three uniforms and one pair of cleats.

→ Equation A

Ian spent $757, before taxes, and purchased five uniforms and two pair of cleats.

→ Equation B

Let's calculate → 2(Equation A) - (Equation B)

2(3U+C)-(5U+2C)= 2(451) -757

6U+2C-5U-2C= 145

U=$ 145

3U+C= 451

3(145)+C= 451

C= 451-435

C= $16

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Answer:  a(x) = x^2 + 40 x + 384

Step-by-step explanation:

Since, here the length of the rectangle is represented by the function l(x) = x + 24,

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And, we know that the area of the rectangle = length of the rectangle l(x) × breadth of the rectangle.

a(x) = l(x) × w(x)

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a(x) = x^2 + 24 x + 16 x + 24\times 16

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4 0
3 years ago
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Alex787 [66]

Answer:

y=-\frac{2}{5}x-\frac{1}{5}

Step-by-step explanation:

The equation of a line is y = mx + b

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First, let's find what m is, the slope of the line.

Let's call the first point you gave, (-3,1), point #1, so the x and y numbers given will be called x1 and y1.

Also, let's call the second point you gave, (2,-1), point #2, so the x and y numbers here will be called x2 and y2.

Now, just plug the numbers into the formula for m above, like this:

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So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

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To find b, think about what your (x,y) points mean:

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Now, look at our line's equation so far: y=-\frac{2}{5}x + b. b is what we want, the --\frac{2}{5} is already set and x and y are just two 'free variables' sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (-3,1) and (2,-1).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!

You can use either (x,y) point you want. The answer will be the same:

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See! In both cases, we got the same value for b. And this completes our problem.

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