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2 years ago

Find the slope of the line, HELPPPP

Mathematics

1 answer:

nlexa [21]2 years ago

7 0

Answer:

Slope: 2

Step-by-step explanation:

The slope of a line is when x increases by an amount, y increases by an amount. We can find the slope of a linear graph by taking 2 points. I will use (0,3) and (-1,1)

We see that the y-values are 4 from each other, and that the x-values are 2 from each other.

Now, we can use a method called rise over run, which is y-value/x-value.

$\frac{4}{2} =2$

Therefore, the slope is 2.

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HELP PLEASE ASAP!!! CORRECT GETS BRAINLIEST!

ASHA 777 [7]

Answer:60

Step-by-step explanation:

5x4x3=60

6 0

3 years ago

Help please, need to show work.

stiks02 [169]

9514 1404 393

Answer:

3. m∠A < 80°

Step-by-step explanation:

The exterior angle NGS, marked as 80°, has a measure that is the sum of the measures of the remote interior angles: GAN, GNA.

If we assume that angle measures cannot be zero, then we must have ...

m∠A +m∠N = 80°

m∠A = 80° -m∠N

Since m∠N > 0, the measure of angle A must be less than 80°.

This conclusion matches choice 3.

8 0

3 years ago

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nirvana33 [79]

Answer:

(16√75)/(5√12) = 8

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Find T5(x) : Taylor polynomial of degree 5 of the function f(x)=cos(x) at a=0 . (You need to enter function.) T5(x)= Find all va

Burka [1]

Answer:

$\bf cos(x)\approx1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{4!}=\\\\=1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{24}$

The polynomial is an approximation with an error less than or equals to 0.002652 for x in the interval

[-1.113826815, 1.113826815]

Step-by-step explanation:

According to Taylor's theorem

$\bf f(x)=f(0)+f'(0)x+f''(0)\displaystyle\frac{x^2}{2}+f^{(3)}(0)\displaystyle\frac{x^3}{3!}+f^{(4)}(0)\displaystyle\frac{x^4}{4!}+f^{(5)}(0)\displaystyle\frac{x^5}{5!}+R_6(x)$

with

$\bf R_6(x)=f^{(6)}(c)\displaystyle\frac{x^6}{6!}$

for some c in the interval (-x, x)

In the particular case f

f(x)=cos(x)

we have

$\bf f'(x)=-sin(x)\\f''(x)=-cos(x)\\f^{(3)}(x)=sin(x)\\f^{(4)}(x)=cos(x)\\f^{(5)}(x)=-sin(x)\\f^{(6)}(x)=-cos(x)$

therefore

$\bf f'(x)=-sin(0)=0\\f''(0)=-cos(0)=-1\\f^{(3)}(0)=sin(0)=0\\f^{(4)}(0)=cos(0)=1\\f^{(5)}(0)=-sin(0)=0$

and the polynomial approximation of T5(x) of cos(x) would be

$\bf cos(x)\approx1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{4!}=\\\\=1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{24}$

In order to find all the values of x for which this approximation is within 0.002652 of the right answer, we notice that

$\bf R_6(x)=-cos(c)\displaystyle\frac{x^6}{6!}$

for some c in (-x,x). So

$\bf |R_6(x)|\leq|\displaystyle\frac{x^6}{6!}|=\displaystyle\frac{|x|^6}{6!}$

and we must find the values of x for which

$\bf \displaystyle\frac{|x|^6}{6!}\leq0.002652$

Working this inequality out, we find

$\bf \displaystyle\frac{|x|^6}{6!}\leq0.002652\Rightarrow |x|^6\leq1.90944\Rightarrow\\\\\Rightarrow |x|\leq\sqrt[6]{1.90944}\Rightarrow |x|\leq1.113826815$

Therefore the polynomial is an approximation with an error less than or equals to 0.002652 for x in the interval

[-1.113826815, 1.113826815]

8 0

3 years ago

A coat at a store is originally priced at $54.99. The store marks the price down to $32.99. To the nearest percent, what is the

Dmitry_Shevchenko [17]

Answer:

66.6%

Step-by-step explanation:

Step one

given

A coat at a store is originally priced at $54.99

The store marks down the price down to $32.99

Required

the percent decrease

Step two:

the percent decrease= change in price/ old price*100

the percent decrease= 54.99-32.99/54.99*100

the percent decrease= 22/ 32.99*100

the percent decrease= 0.666*100

the percent decrease= 66.6%

6 0

3 years ago