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AVprozaik [17]
3 years ago
10

What is the value of m in the equation one-half m minus three-fourths n equals 16, when n equals 8? 20 32 44 48

Mathematics
2 answers:
Fofino [41]3 years ago
4 0

Answer:

the answer is c: 44

hope it helps

:)

FinnZ [79.3K]3 years ago
3 0

Answer:

Step-by-step explanation:

The equation is given: m/2 - 3n/4 = 16

1) When n = 8: m/2 - 24/4 = 16

m/2 - 6 = 16

∴ m = 2 X 22 = 44

2) When n = 20: m/2 - 60/4 = 16

m/2 - 15 = 16

∴ m = 2 X 31 = 62

3) When n = 32: m/2 - 96/4 = 16

m/2 - 24 = 16

∴ m = 2 X 40 = 80

4) When n = 44: m/2 - 132/4 = 16

m/2 - 33 = 16

∴ m = 2 X 49 = 98

5) When n = 48: m/2 - 144/4 = 16

m/2 - 36 = 16

∴ m = 2 X 52 = 104

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slavikrds [6]

ANSWER

y=-\frac{4}{3}x+\frac{16}{3}


Or

3y+4x=16


EXPLANATION


Let us find the gradient of the line:

-3x+4y=4 by rewriting it in the slope intercept form.


\Rightarrow 4y=3x+4


We divide through by 4 now;


\Rightarrow y=\frac{3}{4}x+1


This is now in the form;

y=mx+c

where

m=\frac{3}{4} is he slope.


This implies that the slope of the line that is perpendicular to this line will be the negative reciprocal of m=\frac{3}{4} .


Thus the perpendicular line has slope,

m=\frac{-1}{\frac{3}{4}}= -\frac{4}{3}.


Let the perpendicular line have equation,


y=mx+c

When we substitute the slope we have;


y=-\frac{4}{3}x+c

We substitute the point. (4,0) to find c.


0=-\frac{4}{3}(4)+c


0=-\frac{16}{3}+c


\frac{16}{3}=c

We substitute c to obtain;


y=-\frac{4}{3}x+\frac{16}{3}


Or

3y+4x=16

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