Given:
'a' and 'b' are the intercepts made by a straight-line with the co-
ordinate axes.
3a = b and the line pass through the point (1, 3).
To find:
The equation of the line.
Solution:
The intercept form of a line is
...(i)
where, a is x-intercept and b is y-intercept.
We have, 3a=b.
...(ii)
The line pass through the point (1, 3). So, putting x=1 and y=3, we get
Multiply both sides by a.
The value of a is 2. So, x-intercept is 2.
Putting a=2 in , we get
The value of b is 6. So, y-intercept is 6.
Putting a=2 and b=6 in (i), we get
Therefore, the equation of the required line in intercept form is .
Answer:
(a variation of) vertex form
Step-by-step explanation:
For vertical scale factor "a" and vertex (h, k), the vertex form of the equation for a parabola can be written as ...
y = a(x -h)^2 +k
If k is subtracted from this equation, an alternate form is ...
y -k = a(x -h)^2
This latter version of vertex form is the form your equation has, where ...
=(1,2,3,4,5,6,7,8,9,10,11,12)
kati45 [8]
Answer:
2 and 4 is overlapping :)
Step-by-step explanation:
square numbers only those two
and even numbers=2,4,6,8,10,12
:)