U could easily do this on Photo-math- but here: 6(x−3)
Answer:
h(-2)=-6
g(2)=-7
Step-by-step explanation:
Just plug 2 in for x and solve the equation.
Answer:

Step-by-step explanation:
A circle centered at (0,0) with radius r is 
Since your circle has diameter of 12, then its radius is 6. Then 
So a possible answer is: 
If you want to move the location of the center, but keep it on the x-axis, then add or subtract a number to the x, such as this:

The center of this circle would be (-4, 0) which is still on the x-axis.
Yes, it is possible. For example, let's say that point A is (0,4) and there's a reflection over the y-axis, then point A would still be (0,4).
Numerical hope that helps