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aliina [53]
3 years ago
12

What is 2,153.21 rounded to the hundreds place?

Mathematics
2 answers:
Dmitriy789 [7]3 years ago
7 0

Find the digit in the hundred's place, which is 1. Look to the number right to the right of it. If it is 5 or greater, it increases. It is 5, so 1 becomes 2. All other digits behind it become 0's. Your answer is 2,200.

adelina 88 [10]3 years ago
4 0
2,200 because the 5 will be rounded up
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NOOO LINKKKSS Chose the three comparisons that are true.
Eva8 [605]

Answer:

A, C and E

Step-by-step explanation:

A. 2.7 > 2.10

C. 6.64 > 6.2

E. 7.4 = 7.40

Thus, The three comparisons that are true is A, C and E

<u>-TheUnknownScientist</u>

5 0
3 years ago
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BabaBlast [244]

Answer:

\displaystyle \frac{(a - b)^{2} - {c}^{2} }{{a}^{2} - {(b+ c)}^{2} } + \frac{(b - c)^{2} - {a}^{2} }{{b}^{2} - {(c+ a)}^{2} } + \frac{(c - a)^{2} - {b}^{2} }{{c}^{2} - {(a+ b)}^{2} }=1

Step-by-step explanation:

<u>Algebra Simplifying</u>

We are given the expression:

\displaystyle T=\frac{(a - b)^{2} - {c}^{2} }{{a}^{2} - {(b+ c)}^{2} } + \frac{(b - c)^{2} - {a}^{2} }{{b}^{2} - {(c+ a)}^{2} } + \frac{(c - a)^{2} - {b}^{2} }{{c}^{2} - {(a+ b)}^{2} }

We need to repeatedly use the following identity:

(a^2-b^2)=(a-b)(a+b)

For example, the first numerator has a difference of squares thus we factor as:

(a - b)^{2} - {c}^{2} =(a-b-c)(a-b+c)

The first denominator can be factored also:

{a}^{2} - {(b+ c)}^{2} = (a-b-c)(a+b+c)

Applying the same procedure to all the expressions:

\displaystyle T=\frac{(a - b- c)(a-b+c) }{a-b-c)(a+b+c) } + \frac{(b - c - a)(b-c+a) }{(b-c-a)(b+c+a) } + \frac{(c - a-b)(c-a+b) }{(c-a-b)(c+a+b)}

Simplifying all the fractions:

\displaystyle T=\frac{a - b- c}{a+b+c} + \frac{b-c+a}{b+c+a } + \frac{c-a+b }{c+a+b}

Since all the denominators are equal:

\displaystyle T=\frac{a - b+ c+b-c+a+c-a+b}{a+b+c}

Simplifying:

\displaystyle T=\frac{a +c+b}{a+b+c}

Simplifying again:

T = 1

Thus:

\boxed{\displaystyle \frac{(a - b)^{2} - {c}^{2} }{{a}^{2} - {(b+ c)}^{2} } + \frac{(b - c)^{2} - {a}^{2} }{{b}^{2} - {(c+ a)}^{2} } + \frac{(c - a)^{2} - {b}^{2} }{{c}^{2} - {(a+ b)}^{2} }=1}

8 0
3 years ago
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Naddika [18.5K]

Answer:

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Equation of line in point slope form is given as

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Here  (x1, y1) = (4, -8)

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Simplifying it further  

y = - \frac {5}{2} x + \frac {5}{2} 4 - 8

y = - \frac {5}{2} x + 2

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Hi Mimi!

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And the best answer that relates to the definition is:

C) A fraction where the top number (the "numerator") is 1

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