Question

Please help me with this question!!!!!​

Answer 1

Answer:

Equation of line in slope-intercept form that passes through (4, -8) and is perpendicular to the graph $y= \frac {2}{5} x - 3$ is below

$y = - \frac {5}{2} x + 2$

Step-by-step explanation:

Slope of the equation  $y= \frac{2}{5} x -3$   is  $m_1 = \frac{2}{5}$

Since slopes of perpendicular lines are negative reciprocal of each other, therefore slope of other line is given as

$m_2 = - \frac {1}{m_1} = - \frac {5}{2}$

Equation of line in point slope form is given as

$y-y_1=m_2(x-x_1)$

Here  (x1, y1) = (4, -8)

$y+8 = - \frac{5}{2} (x-4)$

Simplifying it further  

$y = - \frac {5}{2} x + \frac {5}{2} 4 - 8$

$y = - \frac {5}{2} x + 2$