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3 years ago

Thirty cows. Twenty-eight chickens. How many didn't?

Mathematics

1 answer:

Anon25 [30]3 years ago

3 0

20 didn't do it for this one.

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Find the value of 2 over 3 divided by 6

iragen [17]

Answer:

$\frac{1}{9}$

Step-by-step explanation:

$\frac{2}{3}$ ÷ 6

leave the fraction, change division to multiply, turn 6 upside down

= $\frac{2}{3}$ × $\frac{1}{6}$ ( cancel 2 and 6 by 2 )

= $\frac{1}{3}$ × $\frac{1}{3}$

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A box contains 5 red balls, 6 white balls and 9 black balls. Two balls are drawn at

valina [46]

Answer:

$P(Same)=\frac{61}{190}$

Step-by-step explanation:

Given

$Red = 5$

$White = 6$

$Black = 9$

Required

The probability of selecting 2 same colors when the first is not replaced

The total number of ball is:

$Total = 5 + 6 + 9$

$Total = 20$

This is calculated as:

$P(Same)=P(Red\ and\ Red) + P(White\ and\ White) + P(Black\ and\ Black)$

So, we have:

$P(Same)=\frac{n(Red)}{Total} * \frac{n(Red) - 1}{Total - 1} + \frac{n(White)}{Total} * \frac{n(White) - 1}{Total - 1} + \frac{n(Black)}{Total} * \frac{n(Black) - 1}{Total - 1}$

<em>Note that: 1 is subtracted because it is a probability without replacement</em>

$P(Same)=\frac{5}{20} * \frac{5 - 1}{20- 1} + \frac{6}{20} * \frac{6 - 1}{20- 1} + \frac{9}{20} * \frac{9- 1}{20- 1}$

$P(Same)=\frac{5}{20} * \frac{4}{19} + \frac{6}{20} * \frac{5}{19} + \frac{9}{20} * \frac{8}{19}$

$P(Same)=\frac{20}{380} + \frac{30}{380} + \frac{72}{380}$

$P(Same)=\frac{20+30+72}{380}$

$P(Same)=\frac{122}{380}$

$P(Same)=\frac{61}{190}$

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3 years ago

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Answer:

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Step-by-step explanation:

Ok Just Plug it in

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2:9

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