Be more specific. Like what is it asking you to do ? I'm trying to help. :)
Answer:
1.4% of connectors fail during the warranty period.
Step-by-step explanation:
We have these following probabilities:
A 90% probability that a connector is kept dry.
A 10% probability that a connectors is wet.
If a connector is dry, an 1% probability of failling.
If a connector is wet, a 5% probability of failling.
What proportion of connectors fail during the warranty period?
This is 1% of 90% and 5% of 10%. So

1.4% of connectors fail during the warranty period.
5/3 is greater improper fraction comes out to 1 2/3
Answer:
- -1392.09
- -1744.43
- -1636.41
Step-by-step explanation:
using the given integral
calculate: Δx = (12-0) / 8 = 3/2
Xo = 0, f(x) = 
X1 = 3/2 , X2 = 3, X3 = 9/2, X4 = 6, X5 = 15/2, X6 = 9, X7 = 21/2, X8 = 12
Inputting the given values into the Trapezoid rule, midpoint rule and Simpson's rule to approximate the given integral with the specified value of n = 8
Answer:
93.1%
Step-by-step explanation: