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3 years ago

Can anybody help me ?????????????????????? please geometry

Mathematics

2 answers:

AVprozaik [17]3 years ago

7 0

Where the angle bisectors intersect determines the center of the incircle.
Where the side perpendicular bisectors intersect determines the center of the center of the circumcircle. From these definitions, you should be able to determine the points you want.

Ulleksa [173]3 years ago

7 0

See, pls, the suggested explanation:
S - the centre of inscribed circle, P - the centre of circumscribed circle.
Details are in the attached picture: red lines for small circle (inscribed), green ones for large (circumscribed).

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The graph shows a square root function. A curve starts on the y-axis in quadrant 4 and goes into quadrant 1. The curve opens dow

Naily [24]

Answer:

A and B are the answers on Edge.

Step-by-step explanation:

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3 years ago

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Triangle DEF has sides with lengths of 6, 11, and 13 units. Determine whether this triangle is a right triangle. Show all work n

mario62 [17]

Answer:

Triangle DEF is not a right triangle ; possible lengths are 20 & 15

Step-by-step explanation:

For right triangle;

the sum of the square of the two adjacent sides must equal the square of the hypotenus.

Therefore, (6^2)+(11^2)≠(13^2).

the possible length are 20 & 15 because

(20^2)+(15^2)=(25^2)

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3 years ago

what is the least possible value of the smallest of 99 consecutive positive integers whose sum is a perfect cube

Dmitrij [34]

Let the least possible value of the smallest of 99 cosecutive integers be x and let the number whose cube is the sum be p, then

$\frac{99}{2} (2x+98)=p^3 \\ \\ 99x+4,851=p^3\\ \\ \Rightarrow x=\frac{p^3-4,851}{99}$

By substitution, we have that $p=33$ and $x=314$ .

Therefore, the least possible value of the smallest of 99 consecutive positive integers whose sum is a perfect cube is 314.

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4 years ago

Kailee has 4/5 finished of her math

Helen [10]

Answer:

1/5

Step-by-step explanation:

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3 years ago

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kifflom [539]

Answer:

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Step-by-step explanation:

Your goal is to make the second numbers, "1." So divide the first numbers by the second number to simplify.

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3 years ago