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Lelechka [254]
3 years ago
9

Someone do this for me plzzz.

Mathematics
2 answers:
olya-2409 [2.1K]3 years ago
8 0
The answer is A for that problem
Juliette [100K]3 years ago
3 0
ITS CORRECT WHAT THE PEOPLE SAID AT THE ITS A
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Lannister checks out 6 set of books from the library each set has the same number of books she reads 7 of the books and she has
fgiga [73]

Answer:

3

Step-by-step explanation:

Lannister checks out 6 sets of book

Each set had the same number of books

She reads 7 books and has 11 more to go

Therefore the number of books in each set can be calculated as follows

= 11+7

= 18

18/6

= 3

Hence there are 3 books in each set

6 0
3 years ago
Find the square of each imaginary number.<br> (Get rid of the i)
Dovator [93]

Answer:

- 32/21 over 5 is

Step-by-step explanation:

*gets coins and runs to the store to get "milk"

7 0
3 years ago
Read 2 more answers
If f x = 7x<br><br> 2 − 4x − 10, then f −3 =?
Schach [20]

Answer:

f(x)=xy3 -4xy2 -7x+10

Step-by-step explanation:

the xy3 and xy2 means x to the 3rd power and x to the second power

7 0
3 years ago
6a+(8b+2a)=6a+(2a+8b)=0 <br><br>please help me solve this
solniwko [45]
<span>Simplifying (6a + -8b)(6a + 8b) = 0 Multiply (6a + -8b) * (6a + 8b) (6a * (6a + 8b) + -8b * (6a + 8b)) = 0 ((6a * 6a + 8b * 6a) + -8b * (6a + 8b)) = 0 Reorder the terms: ((48ab + 36a2) + -8b * (6a + 8b)) = 0 ((48ab + 36a2) + -8b * (6a + 8b)) = 0 (48ab + 36a2 + (6a * -8b + 8b * -8b)) = 0 (48ab + 36a2 + (-48ab + -64b2)) = 0 Reorder the terms: (48ab + -48ab + 36a2 + -64b2) = 0 Combine like terms: 48ab + -48ab = 0 (0 + 36a2 + -64b2) = 0 (36a2 + -64b2) = 0 Solving 36a2 + -64b2 = 0 Solving for variable 'a'. Move all terms containing a to the left, all other terms to the right. Add '64b2' to each side of the equation. 36a2 + -64b2 + 64b2 = 0 + 64b2 Combine like terms: -64b2 + 64b2 = 0 36a2 + 0 = 0 + 64b2 36a2 = 0 + 64b2 Remove the zero: 36a2 = 64b2 Divide each side by '36'. a2 = 1.777777778b2 Simplifying a2 = 1.777777778b2 Take the square root of each side: a = {-1.333333333b, 1.333333333b}</span>
4 0
3 years ago
A student saves $3 dollars on August 1, $5 on August 2, $7 on August 3, and so on. How much will she save in August 20 ?
Delvig [45]
Here is your answer

Money saved on each successive day is-

$3, &5, $7....

Clearly it forms an AP,

where

a1= 3

common difference, d= 2

n=20

So,

using formula

Tn= a1+(n-1)d

T20= 3+(20-1)2

= 3+ 19×2

= 3+ 38

=41

So, money saved on August 20= $41

Sum of money saved upto August 20 =
n/2 (a1+T20)
= 20/2 (3+41)
= 10× 44
= $440

HOPE IT IS USEFUL
5 0
3 years ago
Read 2 more answers
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