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Jobisdone [24]
3 years ago
14

What is the definition of "potential energy"?

Computers and Technology
2 answers:
mylen [45]3 years ago
6 0
<span>The energy that a piece of matter has because of its position or because of the arrangement of parts </span>
muminat3 years ago
4 0
Well potential energy is energy that is in a object while its not moving so i would go your third option 
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List one unprofessional AND one professional example of internet/social media
Leni [432]

Professional: Using social media to advertise a company you created

Unprofessional: Using social media to watch cat videos

4 0
2 years ago
Perform depth-first search on each of the following graphs; whenever there's a choice of vertices, pick the one that is alphabet
Vikki [24]

Answer:

See the table attached for complete solution to the problem.

7 0
3 years ago
Write a function listLengthOfAllWords which takes in an array of words (strings), and returns an array of numbers representing t
vesna_86 [32]

Answer:

   public static int[] listLengthOfAllWords(String [] wordArray){

       int[] intArray = new int[wordArray.length];

       for (int i=0; i<intArray.length; i++){

           int lenOfWord = wordArray[i].length();

           intArray[i]=lenOfWord;

       }

       return intArray;

   }

Explanation:

  1. Declare the method to return an array of ints and accept an array of string as a parameter
  2. within the method declare an array of integers with same length as the string array received as a parameter.
  3. Iterate using for loop over the array of string and extract the length of each word using this statement  int lenOfWord = wordArray[i].length();
  4. Assign the length of each word in the String array to the new Integer array with this statement intArray[i]=lenOfWord;
  5. Return the Integer Array

A Complete Java program with a call to the method is given below

<em>import java.util.Arrays;</em>

<em>import java.util.Scanner;</em>

<em>public class ANot {</em>

<em>    public static void main(String[] args) {</em>

<em>       String []wordArray = {"John", "James", "David", "Peter", "Davidson"};</em>

<em>        System.out.println(Arrays.toString(listLengthOfAllWords(wordArray)));</em>

<em>        }</em>

<em>    public static int[] listLengthOfAllWords(String [] wordArray){</em>

<em>        int[] intArray = new int[wordArray.length];</em>

<em>        for (int i=0; i<wordArray.length; i++){</em>

<em>            int lenOfWord = wordArray[i].length();</em>

<em>            intArray[i]=lenOfWord;</em>

<em>        }</em>

<em>        return intArray;</em>

<em>    }</em>

<em>}</em>

This program gives the following array as output: [4, 5, 5, 5, 8]

7 0
3 years ago
Two machines can finish a job in StartFraction 20 Over 9 EndFraction hours. Working​ alone, one machine would take one hour long
Alborosie

<em><u>Answer</u></em>

5 hours

<em><u>Explanation</u></em>

The two working together can finish a job in

\frac{20}{9}  \: hours

Also, working alone, one machine would take one hour longer than the other to complete the same job.

Let the slower machine working alone take x hours. Then the faster machine takes x-1 hours to complete the same task working alone.

Their combined rate in terms of x is

\frac{1}{x}    +  \frac{1}{x - 1}

This should be equal to 20/9 hours.

\frac{1}{x}  +  \frac{1}{x - 1}  =  \frac{9}{20}

Multiply through by;

20x(x - 1) \times \frac{1}{x}  +20x(x - 1) \times   \frac{1}{x - 1}  =  20x(x - 1) \times \frac{9}{0}

20(x - 1)  +20x = 9x(x - 1)

20x - 20+20x = 9{x}^{2}  - 9x

9{x}^{2}  - 9x - 20x - 20x + 20= 0

9{x}^{2}  - 49x  + 20= 0

Factor to get:

(9x - 4)(x - 5) = 0

x =  \frac{4}{9}  \: or \: x = 5

It is not feasible for the slower machine to complete the work alone in 4/9 hours if the two will finish in 20/9 hours.

Therefore the slower finish in 5 hours.

8 0
3 years ago
To all paladins players out there!!!!!
Alex777 [14]

I am BORED PPL ..........

Explanation:

hi

6 0
3 years ago
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