Knowing that the area of a square is equivalent the square of its side length, the length of one side can be calculated by taking the square root of the area. The square root of the expression 9q^4r^8s^8 units is equivalent to <span>3q2r4|s3| units. When taking the square root of variables, the power they are raised to is divided by 2.</span>
Answer:
SEE BELOW IN BOLD.
Step-by-step explanation:
a.
h = -16t^2 + 50t
h = 20 t
When the height is the same:
-16t^2 + 50t = 20t
-16t^2 + 30t = 0
t(-16t + 30) = 0
t = 0 or -16t + 30 = 0, so:
t = 0 or -30/-16 = 1.875
So the answer is 1.88 seconds to the nearest hundredth.
b.
For the ball
h = -16t^2 + 50t
Finding the derivative and equating to zero:
dh/dt = -32t + 50 = 0
t = -50/-32 = 1.563
Maximum height after 1.56 seconds to nearest hundredth
c.
When the ball hits the ground h = 0 so
-16t^2 + 50t = 0
-16t(t - 50/16)= 0
T = 3.13 SECONDS TO THE NEAREST HUNDERDTH
Answer:
The margin of error for a 90% confidence interval is 16.4
Step-by-step explanation:
We are given the following in the question:
Sample size, n = 25
Standard deviation = 50

Margin of error =

Putting the values, we get,

Thus, the margin of error for a 90% confidence interval is 16.4
√65Explanation:(−5,1)=x1,y1(3,0)=x2,y2The distance is calculated using formula:'Distance =√(x2−x1)2+(y2−y1)2=√(3−(−5))2+(0−1)2=√(3+5)2+(−1)2=√(8)2+(−1)2=√(64+1)Distance =√65