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3 years ago

7

The chapter is 8 pages long. Kosta read 1/4 of the chapter aloud. Then Christina read three pages to the class. How many pages h

ave they read so far.

2 answers:

Evgen [1.6K]3 years ago

3 0

Ok so 1/4
1/4 of 8=1/4 times 8=8/4=2
2 pages read

then 3 pages
2+3=5
total is 5 pages

Anni [7]3 years ago

3 0

1/4 of the chapter = 2 pages
2 + 3 = 5

The have read 5 pages so far

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Six friends attend a party. They form pairs for a game. How many different pairs are possible?

Leona [35]

Pairs, in this case, relates to a group of 2 or more. We have 6 friends. Let's call them A,B,C,D,E,F. This will allow us to make a [some sort of] combination tree:

1. ABC against DEF

2. ABD against CEF

3. ABE against CDF

4. ABF against CDE

5. ACD against BFE

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7. ACF against BDE

8. ADE against BCF

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3 years ago

Suppose you choose a team of two people from a group of n > 1 people, and your opponent does the same (your choices are allow

jonny [76]

Answer:

The number of possible choices of my team and the opponents team is

$\left\begin{array}{ccc}n-1\\E\\n=1\end{array}\right i^{3}$

Step-by-step explanation:

selecting the first team from n people we have $\left(\begin{array}{ccc}n\\1\\\end{array}\right) = n$ possibility and choosing second team from the rest of n-1 people we have $\left(\begin{array}{ccc}n-1\\1\\\end{array}\right) = n-1$

As { A, B} = {B , A}

Therefore, the total possibility is $\frac{n(n-1)}{2}$

Since our choices are allowed to overlap, the second team is $\frac{n(n-1)}{2}$

Possibility of choosing both teams will be

$\frac{n(n-1)}{2} * \frac{n(n-1)}{2} \\\\= [\frac{n(n-1)}{2}] ^{2}$

We now have the formula

1³ + 2³ + ........... + n³ = $[\frac{n(n+1)}{2}] ^{2}$

1³ + 2³ + ............ + (n-1)³ = $[x^{2} \frac{n(n-1)}{2}] ^{2}$

= $\left[\begin{array}{ccc}n-1\\E\\i=1\end{array}\right] = [\frac{n(n-1)}{2}]^{3}$

4 0

4 years ago

Can you help me on this one? I kinda forgot this whole unit Lowkey so can you explain it as if there were someone who never lear

DIA [1.3K]

Answer:

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answer is at the bottom if needed

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

The weights of adult male birds of a certain species are normally distributed with a mean of 27.5 grams and a standard deviation

Korvikt [17]

Answer:

The z-score of a male bird of this species with a weight of 29.37 grams is 1.7.

Step-by-step explanation:

We are given that the weights of adult male birds of a certain species are normally distributed with a mean of 27.5 grams and a standard deviation of 1.1 grams.

<u><em>Let X = weights of adult male birds of a certain species</em></u>

So, X ~ Normal( $\mu=27.5,\sigma^{2} =1.1^{2}$ )

The z score probability distribution for normal distribution is given by;

Z = $\frac{ X-\mu}{\sigma } }$ ~ N(0,1)

where, $\mu$ = population mean weight = 27.5 grams

$\sigma$ = standard deviation = 1.1 grams

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

SO, the z-score of a male bird of this species with a weight of 29.37 grams is given by;

<u>Z score</u> = $\frac{ X-\mu}{\sigma } }$ = $\frac{ 29.37-27.5}{1.1 } }$

= <u>1.7</u>

4 0

3 years ago

The point (8,-4) lies on a circle. What is the length of the radius of this circle if the center is located at (5,-7)

Kamila [148]

Notice the picture, the radius is just the distance from the
center to a point on the circle, thus

$\bf \textit{distance between 2 points}\\ \quad \\\\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{5}}\quad ,&{{ -7}})\quad 
% (c,d)
&({{ 8}}\quad ,&{{ -4}})
\end{array}\qquad 
% distance value
\\\\\\
\begin{array}{llll}
d = &\sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}\\
&\qquad \uparrow \\
&radius
\end{array}$

$\bf \begin{array}{llll}
d = &\sqrt{({{ 8}}-{{ 5}})^2 + ({{ -4}}-{{(-7)}})^2}\\
&\qquad \uparrow \\
&radius
\end{array}
\\\\\\
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\\\\\\
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4 0

4 years ago