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cupoosta [38]
3 years ago
10

Find the coordinates of line segment A' B' with pre - image A (1, 6) and B (2, -4) and scale

Mathematics
1 answer:
OverLord2011 [107]3 years ago
3 0
Can u show the image
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Man, what type of powder u trynna find?
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Find f^-1(x) for f(x) = 1/x^3
kow [346]

Answer: f^{-1}(x) = \frac{\sqrt[3]{x^{2}}}{x}

<u>Step-by-step explanation:</u>

y = \frac{1}{x^{3}}

Inverse is when you swap the x's and y's and then solve for "y":

x = \frac{1}{y^{3}}

y^{3} = \frac{1}{x}

y = \frac{1}{\sqrt[3]{x}}

y = \frac{1}{\sqrt[3]{x}}*(\frac{\sqrt[3]{x}}{\sqrt[3]{x}})^{2}

y = \frac{\sqrt[3]{x^{2}}}{x}

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3 years ago
2x - 2y = 2 and 7 = -x​
Elina [12.6K]

Answer:

y = -6

Step-by-step explanation:

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Could someone please answer question b) ii) ?<br> The question is on the attached image.
mel-nik [20]

Answer:

b) i) Curve A

ii) - 1.75

iii) x = 1 - √5  or x = 1 + √5

Step-by-step explanation:

b) i) We are given a function y = x² - 2x - 3 and the graph of this function is also shown in the side diagram.

The equation can be rearranged to y = (x - 1)² - 4

⇒ (x - 1)² = y + 4

Therefore, this is an equation of a parabola having the vertex at (1,-4) point and its axis is parallel to the positive y-axis.

So, the curve A represents the equation given. (Answer)

ii) Now, at x = 2.5, f(x) = 2.5² - 2 × 2.5 - 3 = - 1.75 (Answer)

iii) When y = 1, then x² -2x - 3 = 1

⇒ x² - 2x - 4 = 0

⇒ (x - 1)² - 5 = 0

⇒ (x - 1)² - (√5)² = 0

⇒ (x - 1 + √5)(x - 1 - √5) = 0

⇒ x = 1 - √5  or x = 1 + √5 (Answer)

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4 years ago
Student ID number consists of 6 characters. The first four
ser-zykov [4K]

Answer:

b. 4,264,650

Step-by-step explanation:

(9 * 9 * 9 * 9) * (26 * 25)

6 0
3 years ago
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