What is the (Highest Common Factor) HCF of 77, 91 and 143. Also give its index notation
2 answers:
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Answer:
0.0588 = 5.88% probability that a middle-aged man with diabetes is very active
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is
In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Has diabetes.
Event B: Is very active.
Probability of having diabetes:
To find this probability, we take in consideration that:
It also found that men who were very active (burning about 3,500 calories daily) were a fourth as likely to develop diabetes compared with men who were sedentary. Assume that one-fifth of all middle-aged men are very active, and the rest are classified as sedentary.
So the probability of developing diabetes is:
x of 4/5 = x of 0.8(not active)
x/4 = 0.25x of 1/5 = 0.2(very active). So
Probability of developing diabetes while being very active:
0.25x of 0.2. So
What is the probability that a middle-aged man with diabetes is very active?
0.0588 = 5.88% probability that a middle-aged man with diabetes is very active
Hello,
Rectangle A: 6cm (x+2)cm
Rectangle B: 3cm (2x+1)cm
The formula for the perimeter of a rectangle is: P=2(base+height)
Then:
![P_A=2(b+h) \\ P_A=2*[6+(x+2)] \\ P_A=2*(x+8) \\ P_A=2x+16 \\ \\ \\ P_B=2(b+h) \\ P_B=2*[3+(2x+1)] \\ P_B=2*(2x+4) \\ P_B=4x+8 ](https://tex.z-dn.net/?f=P_A%3D2%28b%2Bh%29%20%5C%5C%20P_A%3D2%2A%5B6%2B%28x%2B2%29%5D%20%5C%5C%20P_A%3D2%2A%28x%2B8%29%20%5C%5C%20P_A%3D2x%2B16%20%5C%5C%20%20%5C%5C%20%20%5C%5C%20P_B%3D2%28b%2Bh%29%20%5C%5C%20P_B%3D2%2A%5B3%2B%282x%2B1%29%5D%20%5C%5C%20P_B%3D2%2A%282x%2B4%29%20%5C%5C%20P_B%3D4x%2B8%0A)
But we know that the perimeters are the same, so:
With the answer of A, we realize that this figure is actually a square.
Rectangle A: 6cm (x+2)cm
Rectangle B: 3cm (2x+1)cm
The formula for the perimeter of a rectangle is: P=2(base+height)
Then:
But we know that the perimeters are the same, so:
With the answer of A, we realize that this figure is actually a square.