ANSWER
EXPLANATION
The given angle is 870°.
870°-360°-360°=150°
This means that:
870° is coterminal with 150°, hence its terminal side is in the second quadrant.
It makes an acute angle of 30° with the x-axis.
Note that cotangent is negative in the second quadrant,
Hence,
The first option is correct.
X - ( 1 / 2 )x - ( 1 / 3)x = 6x / 6 - 3x / 6 - 2x / 6 = ( 1 / 6 )x, where x is full tank of gas
The answer is 1 / 6 of the gas have left ;
Answer:
1) 675,000.
2) 356,000
Step-by-step explanation:
There are some rules to round off to the nearest thousand.
1. While rounding off to the nearest thousand, if the digit in the hundreds place is between 0 – 4 i.e., < 5, then the hundreds place is replaced by ‘0’.
2. If the digit in the hundreds place is = to or > 5, then the hundreds place is replaced by ‘0’ and the thousands place is increased by 1.
We have given two numerals:
1)<u> 674,620</u>
According to the second rule defined the digit at the hundreds place is greater than 5 than the thousands place will be increased by 1.
The answer is 675,000.
2) <u>355,500</u>
According to the second rule defined the digit at the hundreds place is greater than 5 than the thousands place will be increased by 1.
The answer is 356,000....
Answer:
7.06 x 10^(-7) ft 3
Step-by-step explanation:
We have the formula to calculate the volume of an octagonal Pyraamid as following:
<em>+) Volume of octagonal pyramid = 1/3 * Area of the base * Height</em>
As given, the base of the pyramid is an octagon with area equal to 15mm2
=> Area of the base = 15 mm2
The height of the pyramid is the length of the line segment which is perpendicular to the base - which is the red line.
=> Height = 4mm
So we have:
<em>Volume of octagonal pyramid = 1/3 * Area of the base * Height</em>
<em>= 1/3 * 15 * 4 = 20 mm3</em>
<em />
As: 1 mm3 = 3.53 x 10^(-8) ft 3
=> 20 mm3 = 7.06x10^(-7) ft 3
So the volume of the pyramid is : 7.06 x 10^(-7) ft 3
So y+x=2
x-y=4
one way is subsituteion where yousubisutte one of the number for another exg
x-y=4
add y to both sides
x=y+4
subsitute y+4 for x in x+y=2
y+4+y=2
2y+4=2
subtract 4 from both sides
2y=-2
divide both sides by 2
y=-1
subsiutte
x+y=2
x-1=2
x=3
or elimination
x+y=2
x-y=4
add the two equations and cancel the y terms
x+x+y-y=2+4
2x=6
divide both sides by 2
x==3
subsitute
x+y=2
3+y=2
y=-1
so x=3
y=-1
