(tanθ + cotθ)² = sec²θ + csc²θ
<u>Expand left side</u>: tan²θ + 2tanθcotθ + cot²θ
<u>Evaluate middle term</u>: 2tanθcotθ = 
= 2
⇒ tan²θ + 2+ cot²θ
= tan²θ + 1 + 1 + cot²θ
<u>Apply trig identity:</u> tan²θ + 1 = sec²θ
⇒ sec²θ + 1 + cot²θ
<u>Apply trig identity:</u> 1 + cot²θ = csc²θ
⇒ sec²θ + csc²θ
Left side equals Right side so equation is verified
Hello there!
Your answer would be
CAT (top line) = DBU (bottom line)
CAT (bottom line) = BZS (top line)
Hope I helped!
Let me know if you need anything else!
~ Zoe
3 dimes= 30 cent
4 pennnies= 4
30+4= 34 cents
To solve this question, we just need to insert 12 into the m position of each question and see if the equation holds true.
a. 4m = 40
4(12) = 40
48 = 40
48 obviously does not equal 40, so it is not choice A.
b. m + 20 = 42
12 + 20 = 42
32 = 42
Again, 32 isn't the same as 42, so not choice B either.
c. 4m = 48
4(12) = 48
48 = 48
It looks like this one is true, but let's solve D also just to make sure.
d. m - 4 = 9
12 - 4 = 9
8 = 9
This is false, since 8 does not equal 9.
Therefore, choice C (4m = 48) is the correct answer.
Hope that helped! =)
Photo????? i need more context:)
