3(m + 5 + 9m)
A.
(1) 3m + 15 + 27m
(2) 3(10m + 5)
B. 3(m + 5 + 9m)....distributive property
(3 * m) + (3 * 5) + (3 * 9m) =
3m + 15 + 27m
C. 3(m + 5 + 9m) = 3(10m + 5)......m = 1
3(1 + 5 + 9(1) = 3(10(1) + 5)
3(1 + 5 + 9) = 3(10 + 5)
3(15) = 3(15)
45 = 45
Whats the problem?
756/35=21,6
Answer:
a = 180 - b - c
Step-by-step explanation:
given 180 = a + b + c or
a + b + c = 180 ( isolate a by subtracting b from both sides then c )
subtract b from both sides
a + c = 180 - b
subtract c from both sides
a = 180 - b - c
An important rule of logs is a*log b = log b^a.
Thus, 2 (log to the base 5 of )(5x^3) = (log to the base 5 of ) (5x^3)^2, or
(log to the base 5 of ) (25x^6).
Next, (1/3) (log to the base 5 of ) (x^2+6) = (log to the base 5 of ) (x^2+6)^(1/3).
Here, the addition in the middle of the given expression indicates multiplication:
2Log5(5x^3)+1/3log5(x^2+6) = (log to the base 5 of ) { (5x^3)^2 * (x^2+6)^(1/3) }.
Here we've expressed the given log quantity as a single log.
From sin(180-x) = sin(x)
sin(150) = sin(180-30) = sin(30)
sin(120) = sin(180-60) = sin(60)
from cos(360-x) = cos(x)
cos(300) = cos(360-60) = cos(60)
cos(210) = cos(360-150) = cos(150)
from cos(180-x) = -cos(x)
cos(210) = cos(150) = cos(180-30) = -cos(30)
