Answer: 7 rides
Step-by-step explanation:
Since it takes $4 to enter the fair, you have
$21.50 - $4 = $17.50 left to spend on rides
$17.50/$2.50 = 7 rides
hope this helps!
Answer:
400000
Step-by-step explanation:
your welcome
Nothing else is given, so for the two triangles to be congruent, the only possible proof is the ASA theorem.
first pairs of angles: 2x+7=x+21 => x=14
second pairs of angles: 8y-4=4y+28 =>y=8
The two triangles share the same side PR
Based on the Angle-Side-Angle Triangle Congruence theorem, these two triangles are congruent with x=14, y=8
(2x+7) +(8y-4) +Q=180 =>85
Answer:

Step-by-step explanation:
The Maclaurin series of a function f(x) is the Taylor series of the function of the series around zero which is given by

We first compute the n-th derivative of
, note that

Now, if we compute the n-th derivative at 0 we get

and so the Maclaurin series for f(x)=ln(1+2x) is given by

Answer:
The correct result would be f(g) = g * $1 - $50.
Step-by-step explanation:
If you would like to find the function that gives the profit Betty makes by selling a number of glasses of lemonade, you can find this using the following steps:
p ... profit
g ... glasses of lemonade
f(g) = p = g * $1 - $50
Read more on Brainly.com - brainly.com/question/1638432#readmore