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3 years ago

Don't mind my work but can someone give the answer for 50

Mathematics

2 answers:

Sever21 [200]3 years ago

8 0

The surface area of Micah's ramp is
(12 + 13 + 5 ) * 6 + 2 ( 1/2 * 12 * 5 )
30 * 6 + 60
180 + 60
240 ft

Charra [1.4K]3 years ago

5 0

The answer to question 50 is A. 240 square feet

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From an aeroplane vertically above a straight horizontal plane, the angles of depression of two consecutive kilometres stones on

Airida [17]

You have to build the triangles.

They are such that:
h is the common height
x is the horizontal distance from the plane to one stone
Beta is the angle between x and the hypotenuse

Then in this triangle: tan(beta) = h / x ......(1)

1 - x is the horizontal distance from the plane to the other stone
alfa is the angle between 1 - x and h

Then, in this triangle: tan (alfa) = h / [1 -x ] ...... (2)

from (1) , x = h / tan(beta)

Substitute this value in (2)

tan(alfa) = h / { [ 1 - h / tan(beta)] } =>

{ [ 1 - h / tan(beta) ] } tan(alfa) = h

[tan(beta) - h] tan(alfa) = h*tan(beta)

tan(beta)tan(alfa) - htan(alfa) = htan(beta)

h [tan(alfa) + tan(beta) ] = tan(beta) tan (alfa)

h = tan(beta)*tan(alfa) / (t an(alfa) + tan(beta) )

4 0

4 years ago

What is the period of y=3cot(4x−3π)

Stells [14]

Hello!

hint: we can rewrite your function as below:

3/tan(4x−3π) = 3(1+tan4xtan3π)/tan4x−tan3π =

=3/tan(4x) = 3cot(4x)

now, since the period P of cotangent function is pi, then the period of cot(4x), which is the period of our original function, is such that:

"4P=π"

Hope this Helps! Have A Wonderful Day! :)

4 0

3 years ago

Using the binomial theorem , obtain the expansion of :

andrezito [222]

Answer:

see explanation

Step-by-step explanation:

Expand both factors and collect like term

Using Pascal' triangle with n = 6 to obtain the coefficients

1 6 15 20 15 6 1

Decreasing powers of 1 from $1^{6}$ to $1^{0}$

Increasing powers of 3x from $(3x)^{0}$ to $(3x)^{6}$

$1+3x)^{6}$

= 1. $1^{6}$ $(3x)^{0}$ + 6. $1^{5}$ $(3x)^{1}$ + 15. $1^{4}$ $(3x)^{2}$ + 20. $1^{3}$ $(3x)^{3}$ + 15.1² $(3x)^{4}$ + 6. $1^{1}$ $(3x)^{5}$ + 1. $1^{0}$ $(3x)^{6}$

= 1 + 18x + 135x² + 540x³ + 1215 $x^{4}$ + 1458 $x^{5}$ + 729 $x^{6}$

--------------------------------------------------------------------------------------

$(1-3x)^{6}$

= 1. $1^{6}$ $(-3x)^{0}$ + 6. $1^{5}$ $(-3x)^{1}$ + 15. $1^{4}$ $(-3x)^{2}$ + 20. $1^{3}$ $(-3x)^{3}$ + 15.1² $(-3x)^{4}$ + 6. $1^{1}$ $(-3x)^{5}$ + 1. $1^{0}$ $(-3x)^{6}$

= 1 - 18x + 135x² - 540x³ + 1215 $x^{4}$ - 1458 $x^{5}$ + 729 $x^{6}$

----------------------------------------------------------------------------------

Collecting like terms from both expressions

$(1+3x)^{6}$ + $(1-3x)^{6}$

= 2 + 270x² + 2430 $x^{4}$ + 1458 $x^{6}$

----------------------------------------------------

(2)

Using Pascal's triangle with n = 5

1 5 10 10 5 1

Decreasing powers of 1 from $1^{5}$ to $1^{0}$

Increasing powers of 2x from $(2x)^{0}$ to $(2x)^{5}$

$(1+2x)^{5}$

= 1. $1^{5}$ $(2x)^{0}$ + 5. $1^{4}$ $(2x)^{1}$ + 10. $1^{3}$ $(2x)^{2}$ + 10. $1^{2}$ $(2x)^{3}$ + 5. $1^{1}$ $(2x)^{4}$ + 1. $1^{0}$ $(2x)^{5}$

= 1 + 10x + 40x² + 80x³ + 80 $x^{4}$ + 32 $x^{5}$

8 0

3 years ago

Shawna cuts out a square piece of card stock paper for a project. Her partner Tanisha wants to check to see if the cutout is act

My name is Ann [436]

Answer:

Yes

Step-by-step explanation:

Reason is that a square has all the aspects of a parallelogram a rectangle and a rhombus. It gets its congruent diagonals from the rectangle which is congruent

6 0

3 years ago

Solve each of the triangles for each of the unknown ^e= . f=3cm . e= . ^e=

Alja [10]

Answer:

I don't know

Step-by-step explanation:

Use the app and search it instead of waiting.

4 0

2 years ago