7y^2 + 10y + 3
7y^2 + 7y + 3y + 3
(7y^2+7y) + (3y+3)
7y(y+1) + 3(y+1)
(7y+3)(y+1)
So the final answer is <span>(7y+3)(y+1)</span>
Answer:
bonk
Step-by-step explanation:
Cos(A-B) = cosAcosB + sinAsinB
<span>
cos(</span>π/2 - θ) = cos(π/2)cosθ + sin(π/2)sinθ
π/2 = 90°
cos(π/2) = cos90° = 0. sin(π/2) = sin90° = 1
cos(π/2 - θ) = cos(π/2)cosθ + sin(π/2)sin<span>θ
</span>
= 0*cosθ + 1*sin<span>θ = </span>sin<span>θ
Therefore </span>cos(π/2 - θ) = sin<span>θ
QED </span>
Answer:
<h2>(-10, 2, 6)</h2>
Step-by-step explanation:
Given that the total area of the walkway and the pool is w²+17w+66, and the width w, will be found as follows:
A=length×width
A=w²+17w+66
to get the new width we need to factorize the above quadratic form
A=w²+17w+66
=w²+11w+6w+66
=w(w+11)+6(w+11)
=(w+11)(w+6)
From the answer, the width=6 units, length=11 units
