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Lostsunrise [7]
3 years ago
13

Larry graphs the inequality x less-than negative 5 using the steps below. Step 1: Draw a number line, and place an open circle a

t –5. A number line going from negative 10 to 0. An open circle is at negative 5. Step 2: Shade to the left of –5 to represent less than –5. A number line going from negative 10 to 0. An open circle is at negative 5. Everything to the left of the circle is shaded. Step 3: Check work by substitution. x = negative 5 Negative 5 less-than negative 5 False Larry concludes that he must have shaded the number line in the wrong direction. Which best describes the situation? Larry’s graph is incorrect. He should have used a closed circle at –5. Larry’s graph is incorrect. He should have shaded to the right of –5 because the numbers less than –5 are to the right of –5. Larry’s graph is correct. He should have checked his work using a number to the left of –5. Larry’s graph is correct. He should have checked his work using a number to the right of –5.
Mathematics
2 answers:
timurjin [86]3 years ago
4 0

Answer:

Larry’s graph is incorrect.He should used a closed circle at -5

Step-by-step explanation:

GarryVolchara [31]3 years ago
3 0

Answer:

A)Larry’s graph is incorrect. He should have used a closed circle at –5.

Step-by-step explanation:

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Wewaii [24]
(\frac{2}{3})^4= \frac{2^4}{3^4}= \boxed{\frac{16}{81}}
8 0
3 years ago
Consider the following.3x + 3y = 8(a) Find y' by implicit differentiation.(b) Solve the equation explicitly for y and differenti
ludmilkaskok [199]

Answer:

a.y'=-1

b.y'=-1

c.Yes

Step-by-step explanation:

We are given that consider a function

3x+3y=8

Implicit function: That function is a relation in which dependent variable can not be expressed in terms of independent variable

Explicit function: It is that function in which dependent variable can be expressed in terms of independent variable.

a.3x+3y=8

Differentiate w.r.t x then we get

3+3\frac{dy}{dx}=0

3\frac{dy}{dx}=-3

\frac{dy}[dx}=\frac{-3}{3}=-1

\frac{dy}{dx}=y'=-1

b.3x+3y=8

3y=8-3x

y=\frac{8-3x}{3}

Differentiate w.r.t x then we get

\frac{dy}{dx}=\frac{-3}{3}=-1

\frac{dy}{dx}=y'=-1

When we substituting the value of y obtained from part b into a solution of part a then we get

y'=-1

Hence, solutions are consistent.

8 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20-%205%20%7C2x%20%2B%202%7C%20%2B%207%20%5Cgeqslant%20%20-%203" id="TexFormula1" title=" - 5
blagie [28]

Answer:

The inequality that comes from this equation is -2 < x < 0

Step-by-step explanation:

In order to solve this equation, we need to start by solving for the absolute value portion of the equation.

-5l2x + 2l + 7 > -3

-5l2x + 2l > -10

l2x + 2l < 2

Now we need to split the equation into two different portions. One with the absolute value symbol taken away. Then we do it again with the symbol flipped and the answer negated.

2x + 2 < 2

2x < 0

x < 0

And the negated version.

2x + 2 > -2

2x > -4

x > -2

5 0
3 years ago
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tiny-mole [99]
Unit price is $0.81 per bag
8 0
3 years ago
Read 2 more answers
Please help! I will not need help with the graph at the bottom just the equation
gladu [14]

isolate y

move y to the right

4y=-2x-8

divide by 4

y = -1/2x -2

solution is

y=-1/2x-2

6 0
3 years ago
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