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2 years ago

The perimeter of the rectangle below is 120 units. Find the value of y. 5y - 3 4y

Mathematics

1 answer:

vladimir2022 [97]2 years ago

5 0

Answer:

y =7

Step-by-step explanation:

2(5y-3)+2(4y) = 120 units

10y - 6 + 8y = 120 units

18y= 120+6

y = 126/18

y = 7

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Use the data for each plant's growth to determine and

amid [387]

Answer:

plant A is 1.8 plant B is 1.4 The last one is the second choice

Step-by-step explanation:

just did it got it right

6 0

2 years ago

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Evaluate 5x²-3(x-2)+x for x=3

Zepler [3.9K]

Answer:

Step-by-step explanation:

Evaluate 5 x^2 - 3 (x - 2) + x where x = 3:

5 x^2 - 3 (x - 2) + x = 5×3^2 - 3 (3 - 2) + 3

3^2 = 9:

5×9 - 3 (3 - 2) + 3

3 - 2 = 1:

5×9 - 3 + 3

5×9 = 45:

45 - 3 + 3

45 + 3 = 48:

48 - 3

| 4 | 8

- | | 3

| 4 | 5:

Answer: 45

3 0

2 years ago

Can somebody please help me?

9966 [12]

28+28+28= 84

28 x 28 x 28 = 21952

hope it helps!:)

4 0

1 year ago

Ten times an integer is added to seven times it’s square. If the result is 152, what was the original number?

Bess [88]

Answer:

Required number is 4.

Step-by-step explanation:

Let the required number be a.

Given,

Sum of ten times the integer and seven times it’s square is 152.

= > Ten times of a + seven times of it's square = 152

= > 10( a ) + 7( a )^2 = 152

= > 10a + 7a^2 - 152 = 0

= > 7a^2 + 10a - 152 = 0

= > 7a^2 + ( 38 - 28 )a - 152 = 0

= > 7a^2 + 38a - 28a - 152 = 0

= > a( 7a + 38 ) - 4( 7a + 38 ) = 0

= > ( a - 4 )( 7a + 38 ) = 0

= > a = 4 or - 38 / 7

Hence the required number is 4.

3 0

2 years ago

Kristen invests $ 5745 in a bank. The bank 6.5% interest compounded monthly. How long must she leave the money in the bank for i

podryga [215]

Answer:

1. 10.7 years

2. 17.0 years

3. 2nd option

Step-by-step explanation:

Use formula for compounded interest

$A=P\cdot \left(1+\dfrac{r}{n}\right)^{nt},$

where

A is final value, P is initial value, r is interest rate (as decimal), n is number of periods and t is number of years.

In your case,

1. P=$5745, A=2P=$11490, n=12 (compounded monthly), r=0.065 (6.5%) and t is unknown. Then

$11490=5745\cdot \left(1+\dfrac{0.065}{12}\right)^{12t},\\ \\2=(1.0054)^{12t},\\ \\12t=\log_{1.0054}2,\\ \\t=\dfrac{1}{12}\log_ {1.0054}2\approx 10.7\ years.$

2. P=$5745, A=3P=$17235, n=12 (compounded monthly), r=0.065 (6.5%) and t is unknown. Then

$17235=5745\cdot \left(1+\dfrac{0.065}{12}\right)^{12t},$

$3=(1.0054)^{12t},$

$12t=\log_{1.0054}3,$

$t=\dfrac{1}{12}\log_{1.0054}3\approx 17.0\ years.$

3. <u>1 choice:</u> P=$5745, n=12 (compounded monthly), r=0.065 (6.5%), t=5 years and A is unknown. Then

$A=5745\cdot \left(1+\dfrac{0.065}{12}\right)^{12\cdot 5},\\ \\A=5745\cdot (1.0054)^{60}\approx \$7936.39.$

<u>2 choice:</u> P=$5745, n=4 (compounded monthly), r=0.0675 (6.75%), t=5 years and A is unknown. Then

$A=5745\cdot \left(1+\dfrac{0.0675}{4}\right)^{4\cdot 5},\\ \\A=5745\cdot (1.0169)^{20}\approx \$8032.58.$

The best will be 2nd option, because $8032.58>$7936.39

5 0

2 years ago

Read 2 more answers