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blondinia [14]
3 years ago
13

What is the answer?

Mathematics
2 answers:
notka56 [123]3 years ago
5 0
The answer to that is cubic
Snezhnost [94]3 years ago
5 0
Answer is cubic!!!!!!
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.<br> Put f(x) = x2 + 3 in y2.
saveliy_v [14]

Answer:

(X2+3)2

Step-by-step explanation:

First, you have to substitute in what f(x) equals for y since f(x) stands for y.

By doing this, the equation turns into (x2+3)2, because x2+3 is y, and 2 because the original equation way y2.

After you substitute, the answer is (x2+3)2.

5 0
3 years ago
Please help me with this please and thank you
rjkz [21]

Answer:

Alright so the answer is B but I'll explain why because im nice ig.

Step-by-step explanation:

So lets do some calcumalations.

We'll use 1 as n and should get an output of 3 to check these formulas. Since 1 is the first term and 3 is the first term value makes sense alright.

So 9^1-1 is 0 and any number to the 0 power is 1 so that wont work.

3(4)^1-1 = 3(1); that's the answer

4^1-1 = 1, + 3 = 4 so that wont work either

I hope this helps ya have a great afternoon

8 0
2 years ago
Turn the expressions X-4 and 2x+4 into an equation to find X
bekas [8.4K]
X-4=2x+4
-X -X
-4=x+4
-4 -4
X=-8
3 0
4 years ago
Solve the following equation. Remember to check for extraneous solutions 7/(b+3) + 5/(b-3) = (10b-2)/(b²-9).
vlabodo [156]

Answer:

b= 2 is the solution for the given equation.

Step-by-step explanation:

Here, the given expression is:

\frac{7}{(b+3)}  + \frac{5}{(b-3)} = \frac{10b -2}{(b^{2} -9)}

Simplifying Left side, we get

\frac{7}{(b+3)}  + \frac{5}{(b-3)}

= \frac{7(b-3) + 5(b+3)}{(b+3)(b-3)}

Also, by ALGEBARIC IDENTITY:x^{2} -y^{2} = (x+y)(x-y)

So, (b+3)(b-3) = b^{2} -9

So, LHS becomes \frac{7(b-3) + 5(b+3)}{b^{2} -9}

Compare both Left side, Right side we get

\frac{7(b-3) + 5(b+3)}{b^{2} -9} =   \frac{10b -2}{(b^{2} -9)}

or, 7(b-3) + 5(b+3) = 10b -2

⇒ 7b - 21 + 5b + 15 = 10b -2

or, 12b - 10b = 6-2

or, 2b = 4 ⇒ b = 4/2 = 2

⇒ b= 2 is the solution for the given equation.

7 0
4 years ago
Determine whether each relation is a function. Explain. {(2,0), (2, 2), (2, 4), (2, 6)}​
inysia [295]
A function is the relationship between an independent variable (x) and a dependent variable (y). A function can only occur when the independent variable are limited to one use. A function in this case is determined by the { } symbol.

This example is not a function, as the independent variable (2) appears more than once.

The rule is that the independent variable(x) cannot appear more than once as the same value and the dependant variable(y) can appear more than once as the same value.

Hope this helps!
8 0
2 years ago
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