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Zina [86]
4 years ago
9

Fred and Ben each ran laps around the track. Fred completed his run in 16 minutes. Ben completed his run in 3/4 of the amount of

time of Freds run. What was bens time?
Mathematics
1 answer:
m_a_m_a [10]4 years ago
7 0

Answer:

Time required by Ben was 12 minutes.

Step-by-step explanation:

Given:

Time Required for Fred = 16 mins

Ben completed his run in 3/4 of the amount of time of Freds run.

We need to find the time required by Ben.

Now Given that;

Ben completed his run in 3/4 of the amount of time of Freds run.

It means that time required by Ben is equal to 3/4  times time required by Fred.

Time required by Ben = \frac{3}{4}\times  Freds \ run

Time required by Ben = \frac{3}{4}\times 16 = 12\ mins

Hence Time required by Ben was 12 minutes.

You might be interested in
two technicians regularly make repairs when breakdowns occur on an automated production line. the first technican, who services
xxMikexx [17]

Answer:

52.63% probability that thids intial repair was made by the first technican

Step-by-step explanation:

Bayes Theorem:

Two events, A and B.

P(B|A) = \frac{P(B)*P(A|B)}{P(A)}

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.

In this question:

Event A: Incomplete repair

Event B: Made by the first technican.

The first technican, who services 40% of the breakdowns, has 5% chance of making incomplete repair.

This means that P(B) = 0.4, P(A|B) = 0.05.

Probability of an incomplete repair:

5% of 40%(first technican) or 3% of 60%(second technican). So

P(A) = 0.05*0.4 + 0.03*0.6 = 0.038

Given that there is a problem with the production line due to an incomplete repair, what is the probability that thids intial repair was made by the first technican

P(B|A) = \frac{0.4*0.05}{0.038} = 0.5263

52.63% probability that thids intial repair was made by the first technican

8 0
4 years ago
Suppose a random variable, x, follows a Poisson distribution. Let μ = 2.5 every minute, find the P(X ≥ 125) over an hour. Round
Mashutka [201]

Answer:

P(X ≥ 125) = 0.9812

Step-by-step explanation:

To solve this question, we need to understand the Poisson distribution and the normal distribution.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\lambda}*\lambda^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\lambda is the mean in the given interval, which is the same as the variance.

Normal distribution:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The Poisson can be approximated to the normal, with \mu = \lambda, \sigma = \sqrt{\lambda}

Let μ = 2.5 every minute

This is the mean of the Poisson, so \lambda = 2.5n, in which n is the number of minutes.

P(X ≥ 125) over an hour

An hour has 60 minutes, so n = 60, \lambda = 2.5*60 = 150, \sigma = \sqrt{150} = 12.25

Using continuity correction, this is P(X \geq 125 - 0.5) = P(X \geq 124.5), which is 1 subtracted by the pvalue of Z when X = 124.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{124.5 - 150}{12.25}

Z = -2.08

Z = -2.08 has a pvalue of 0.0188

1 - 0.0188 = 0.9812

So

P(X ≥ 125) = 0.9812

8 0
3 years ago
Solve for p: 3/8 +p/8= 3 1/8
Ivenika [448]
Solve for p:
p/8 + 3/8 = 25/8
p/8 + 3/8 = (p + 3)/8:
(p + 3)/8 = 25/8

Multiply both sides of (p + 3)/8 = 25/8 by 8:
(8 (p + 3))/8 = (8×25)/8
(8×25)/8 = (8×25)/8:
(8 (p + 3))/8 = (8×25)/8
(8 (p + 3))/8 = 8/8×(p + 3) = p + 3:p + 3 = (8×25)/8
(8×25)/8 = 8/8×25 = 25:
p + 3 = 25

Subtract 3 from both sides:
p + (3 - 3) = 25 - 3
3 - 3 = 0:
p = 25 - 3
25 - 3 = 22:
Answer: p = 22
4 0
3 years ago
What is the polynomial 3y^2+(y+7)^2-15 after it has be simplified
kogti [31]

Answer:

4y^(2)+14y+31

Step-by-step explanation:

First you need to do (y+7)(y+7)

y^2+7y+7y+49

y^2+14y+49

Add it all together

y^2+14y+49+3y^2-15

4y^(2)+14y+31

4 0
3 years ago
Last one will give brainly to who answers fast +++++++<br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B5x%20-%204%7D%20%20%3D%
stepan [7]

Answer:

the answer I got is 8...........

3 0
3 years ago
Read 2 more answers
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