Ask question

Ask question

All categories

2 years ago

7

Evaluate the following expression for x = –2 and y = –4.

1 answer:

elena55 [62]2 years ago

4 0

Step-by-step explanation:

check your question again

You might be interested in

If A+B+C=<img src="https://tex.z-dn.net/?f=%5Cpi" id="TexFormula1" title="\pi" alt="\pi" align="absmiddle" class="latex-formula"

seraphim [82]

Answer:

$a + b + c = \pi \\ = > c= \pi - a - b \\ < = > \tan(c) = \tan(\pi - a - b) = -\tan(a + b)$

Step-by-step explanation:

we have:

$\tan(a) + \tan(b) + \tan(c) \\ = \tan(a) + \tan(b) - \tan(a + b) \\ = \tan( a) + \tan(b) - \frac{ \tan(a) + \tan(b) }{1 - \tan(a) \tan(b) } \\ = \frac{ ( \tan(a) + \tan(b) ) \tan(a) \tan(b) }{ \tan(a) \tan(b) - 1 } (1)$

we also have:

$\tan(a) \tan(b) \tan(c) \\ = - \tan(a) \tan(b) \tan(a + b) \\ = \frac{ -(\tan( a ) + \tan(b) ) \tan(a) \tan(b) }{1 - \tan(a) \tan(b) } \\ = \frac{( \tan(a) + \tan(b)) \tan(a) \tan(b) }{ \tan(a) \tan(b) - 1 } (2)$

from (1)(2) => proven

5 0

2 years ago

5 times marys age is the same as 28 less than 7 times her age. Find her age

Gnom [1K]

setup a simple algebraic equation and solve.

5x = 7x-28

-5x -5x

0=2x-28

+28 +28

28=2x

Now divide both sides by 2 and you get that she is 14

3 0

2 years ago

Read 2 more answers

I know how many line of symmetry but i dont know how to explain how i found the lines so can someone do it for me?

11111nata11111 [884]

2 because there are 4 numbers of edges and 4 vertices

7 0

2 years ago

Find the tenth term in the sequence

attashe74 [19]

Answer: The tenth term in the sequence is 512.

Step-by-step explanation:

Since we have given that

$a_n=2^{n-1}$

We need to find the tenth term:

It means n = 10

So, it becomes

$a_{10}=2^{10-1}\\\\a_{10}=2^9\\\\a_{10}=2\times 2\times 2\times 2\times 2\times 2\times 2\times 2\times 2\\\\a_{10}=512$

Hence, the tenth term in the sequence is 512.

4 0

2 years ago

An arithmetic sequence is defined by the recursive formula t1 = 11, tn = tn - 1 - 13, where n ∈N and n > 1. Which of these is

galben [10]

coolio

$t_1=11$

$t_n=t_{n-1}-13$

so each term is ound by subtracting 13 from the previous term

an aritmetic sequence can be written as

$t_n=t_1+d(n-1)$ were

$t_n$ is the nth term

$t_1$ is the first term

d is common difference, which can also be found by doing $t_n-t_{n-1}=d$

n=wich term

we know that $t_1=11$ and we can find d

$t_n=t_{n-1}-13$ , $t_n-t_{n-1}=-13=d$

so te general term is $t_n=11-13(n-1)$ which can also be expanded and written as $t_n=-13n+24$

6 0

3 years ago