The average speed of the runner is 12.7 mph and 20.4 km/h
Given that the runner ran 26.2 mile in 2hr and 4 minutes, we start of by converting the time from hours and minutes into minutes and finally hours, since hours is what we need. So, we have
2hr = 120mins
+ 4 mins = 124 mins
124 mins ÷ 60 hour/mins = 2.06 hours.
This means that the runner finished the race in 2.06 hours.
If we are to find the average speed in mile per hour, we have
Average speed = distance ran ÷ time taken
Average speed = 26.2 ÷ 2.06
Average speed = 12.7 mph
From the speed in mph, we can directly convert it to km/hr by saying
1 mph = 1.609 km/h
12.7 mph = 12.7 * 1.609 = 20.4 km/hr
for more, check: brainly.com/question/1989219
Answer:
45.1feet
Step-by-step explanation:
Given the following
∠I=90°
∠G=62°, and
GH = 96 feet = Hypotenuse
Required
IG = Adjacent side
Using the SOH CAH TOA identity
Cos theta = Adj/hyp
Cos 62 =IG/96
IG = 96cos62
IG = 96(0.4695)
IG = 45.1feet
Hence the length of IG to the nearest tenth is 45.1feet
<h2>1) Plants</h2><h2>2) Animals</h2><h2>3) Humans</h2>
Answer:
-1
Step-by-step explanation:
AND means multiply, so if probability is dependent on two things happening, then we will multiply the individual probabilities together.
1. P(A and 1) = 1/4 x 1/6 = 1/24
2. P(C and 2) = 1/4 x 2/6 = 2/24 = 1/12
3. P(B and 3) = 2/4 x 1/6 = 2/24 = 1/12
4. P(A and 4) = 1/4 x 2/6 = 2/24 = 1/12
5. P(C and 3) = 1/4 x 1/6 = 1/24
6. P(B and 2) = 2/4 x 2/6 = 4/24 = 1/6
7. P(a consonant and an odd #) = 3/4 x 2/6 = 6/24 = 1/4
8. P(a consonant and a prime #) = 3/4 x 3/6 = 9/24 = 3/8
9. P(a vowel and a 5) = 1/4 x 0/6 = 0
10. P(a vowel and a number less than 3) = 1/4 x 3/6 = 3/24 = 1/8
11. P(B and 1) = 2/4 x 1/6 = 2/24 = 1/12
Experimental probability is based on something that has already happened, or data that has already been collected.
12. P(1) = 3/30 = 1/10
13. P(2) = 8/30 = 4/15
14. P(3) = 7/30
15. P(4) = 5/30 = 1/6
16. P(5) = 3/30 = 1/10
17. P(6) = 4/30 = 2/15
Hope this helps!
