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BabaBlast [244]
3 years ago
12

What is the slope no games please i will report!

Mathematics
2 answers:
NNADVOKAT [17]3 years ago
8 0
Here the slope is 2/6
Misha Larkins [42]3 years ago
8 0
Hope this helps I know someone answered before me, but I think mine is correct !

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6. A super-bouncy-ball is thrown 25m into the air. The ball falls, rebounds to 70% of the height of the previous bounce and fall
inn [45]

Answer:

The total distance the ball has travelled after it hits the ground the 5th time is of 48.53m.

Step-by-step explanation:

Geometric sequence:

In a geometric sequence, the quotient of consecutive terms is the same. The nth term of a geometric sequence is given by:

a_n = a_1q^{n-1}

In which a_1 is the first term and q is the common ratio.

A super-bouncy-ball is thrown 25m into the air. The ball falls, rebounds to 70% of the height of the previous bounce and falls again.

This means that:

q = 0.7, a_1 = 25*0.7 = 17.5

Then

a_n = a_1q^{n-1}

a_n = 17.5(0.7)^{n-1}

First 5 terms:

a_1 = 17.5

a_2 = 17.5(0.7)^{2-1} = 12.25

a_3 = 17.5(0.7)^{3-1} = 8.58

a_4 = 17.5(0.7)^{4-1} = 6

a_5 = 17.5(0.7)^{5-1} = 4.2

Find the total distance the ball has travelled after it hits the ground the 5th time.

T = 17.5 + 12.25 + 8.58 + 6 + 4.2 = 48.53

The total distance the ball has travelled after it hits the ground the 5th time is of 48.53m.

8 0
3 years ago
Someone please help!!!!!
Masteriza [31]
B and C by SSA (pls mark as brainliest)
5 0
2 years ago
How many 1/3 pounds serving in 4 2/3 pound of cheese
Marysya12 [62]
Change 4 and 2/3 to an improper fraction.
4 + 2/3 = 14/3
There are 14 of the 1/3 lb serving in 4 and 2/3 pounds of cheese.
3 0
3 years ago
Select the relations that are functions.
Arlecino [84]

Answer:

Depending on how the input of each function defined,

  • The first choice \left\lbrace(a, 1),\, (6, 1), \, (C, 1)\right\rbrace,
  • The third choice \left\lbrace(1, a),\, (2, a), \, (3, a)\right\rbrace
  • The fourth choice \left\lbrace(a, a),\, (b, b), \, (c, c)\right\rbrace

might be functions.

Step-by-step explanation:

A function between two sets (domain and range) should

  • be defined for all elements in the domain, and
  • map each element from the domain to exactly one element in the range.

The second choice can't be a function since the element a from the domain is mapped to more than one element in the range.

Keep in mind that a function should be defined for all elements in its domain. For the first relation to be a function, its domain needs to be \lbrace a,\, 6, \, C\rbrace. Similarly, the domain for the third and fourth relations should be \lbrace 1,\, 2, \, 3\rbrace and \lbrace a,\, b, \, c\rbrace

8 0
3 years ago
How do you graph the line with an equation <br> X=3y
beks73 [17]
The dot has to be colored in
6 0
3 years ago
Read 2 more answers
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