Answer:

Step-by-step explanation:

Answer:
A.

Step-by-step explanation:

Answer:
y = 17x-67
Step-by-step explanation:
The one point form of line also called slope point form is given by

where (x1, y1) is the point and m is slope
Given: (x1, y1) = (4,1) and m= 17
Substituting these values in above equation to find equation in point-slope form
(y-1)=17(x-4)
y-1 = 17x-68
y = 17x-67
the point -slope form of equation y = 17x-67