All categories

2 years ago

At the nearest wholesale store, 3 bags of bulk cereal cost $21.75. At this rate, how much would 5 bags of bulk cereal cost?

Mathematics

2 answers:

sertanlavr [38]2 years ago

4 0

Answer:

if three bags cost $21.75, one bag costs $7.25, therefore five bags cost $36.24.

Hope this helped!

Step-by-step explanation:

zhenek [66]2 years ago

3 0

Answer:

5 bags will cost 36.25

Step-by-step explanation:

We can use a proportion to solve. Put the price over the number of bags

21.75 x

---------- = ---------

3 bags 5 bags

Using cross products

21.75 * 5 = 3x

108.75 = 3x

Divide each side by 3

108.75/3 = 3x/3

36.25 =x

5 bags will cost 36.25

You might be interested in

What is the simplified form of...

Alja [10]

Answer: A) 24 to the square root of 3

Step-by-step explanation: Hope this helps!

8 0

3 years ago

Read 2 more answers

3. Is XY Tangent to circle Z? Y 12 X (20 Z 18

Ratling [72]

Answer:

XY is a tangent

Step-by-step explanation:

Given

$XY = 12$

$WY = 20$

$WZ = 8$

Required

Is XY a tangent?

XY is a tangent if:

$WY^2 = XY^2 + WX^2$

Because XY should make a right angle at point X with the circle

Where

$WX = 2 * WZ$

So, we have:

$WY^2 = XY^2 + WX^2$

$WY^2 = XY^2 + (2*WZ)^2$

$WY^2 = XY^2 + (2WZ)^2$

$WY^2 = XY^2 + 4WZ^2$

This gives:

$20^2 = 12^2 + 4*8^2$

$400 = 144 + 256$

$400 = 400$

Yes, XY is a tangent

4 0

2 years ago

the ratio of the circumferences of two circles is 2:3. If the large circle has a radius of 39 cm, what is the radiusof the small

Orlov [11]

C1/C2 = 2/3

2pi r1 / 2pi r2 = r1/r2 = 2/3

r1/39 = 2/3

r1 = 39*2/3 = 26

So, your answer is 26cm

8 0

2 years ago

Read 2 more answers

1) Solve 2 + 7x + 12 = 0 using factoring and the zero product property.

Kazeer [188]

Answer:

7x+14=0, 7x=-14, x= -2

Step-by-step explanation:

add like terms, then get x on one side, number on the other, then divide both sides by 7

4 0

2 years ago

Which pair of funtions is not a pair of inverse functions? please help!!

antiseptic1488 [7]

Answer:

$f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Step-by-step explanation:

we know that

To find the inverse of a function, exchange variables x for y and y for x. Then clear the y-variable to get the inverse function.

we will proceed to verify each case to determine the solution of the problem

case A) $f(x)=\frac{x+1}{6} , g(x)=6x-1$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y+1}{6}$

Isolate the variable y

$6x=y+1$

$y=6x-1$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=6x-1$

therefore

f(x) and g(x) are inverse functions

case B) $f(x)=\frac{x-4}{19} , g(x)=19x+4$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y-4}{19}$

Isolate the variable y

$19x=y-4$

$y=19x+4$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=19x+4$

therefore

f(x) and g(x) are inverse functions

case C) $f(x)=x^{5}, g(x)=\sqrt[5]{x}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=y^{5}$

Isolate the variable y

fifth root both members

$y=\sqrt[5]{x}$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=\sqrt[5]{x}$

therefore

f(x) and g(x) are inverse functions

case D) $f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y}{y+20}$

Isolate the variable y

$x(y+20)=y$

$xy+20x=y$

$y-xy=20x$

$y(1-x)=20x$

$y=20x/(1-x)$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=20x/(1-x)$

$\frac{20x}{1-x}\neq \frac{20x}{x-1}$

therefore

f(x) and g(x) is not a pair of inverse functions

7 0

2 years ago

Read 2 more answers