Answer:
yes above statement is true
Step-by-step explanation:
mark me as brainliest ❤️
Answer:
It is an identity, the proof is in the explanation
Step-by-step explanation:
csc(A)-cot(A)=tan(A/2)
I'm going to start with right hand side
tan(A/2)=(1-cos(a))/(sin(a)) half angle identity
tan(A/2)=1/sin(a)-cos(a)/sin(a) separate fraction
tan(A/2)=csc(a)-cot(a) reciprocal and quotient identities
we are given
62% of the students take math
so,

49% take science

38% take both science and math
n(M∩S)=38
now, we can use union formula
n(M∪S)=n(M)+n(S) -n(M∩S)
now, we can plug values
and we get
n(M∪S)=62+49 -38
n(M∪S)=73
so,
the percentage takes at least one science or math course is 73%..........Answer
Your answer will be 60%
Have a nice day
Volume = (Area of the base)x(Height)
66.85 = 15(H)
66.85/15 = H
H = 4.4567
The height is 4.4567mm.