This is the answer
Hope it helped
Assume that there are 56 students in this class. what is the probability that at least two students share a? birthday
1 answer:
P(at least 2 students have the same birthday)= 1- P(no 2 students have the same birthday)
Because P(A)=1-P(A'), where A is an event, and A' the complement of that event.
P(no 2 students have the same birthday)=
think of the problem as follows. We have an urn of balls, numbered from 1 to 365 (the number of the days of the year.
What is the probability of picking 56 different numbered balls, with replacements?
The first one can be any of the 365
the second any of 364 (since one selection has already been made)
the third any of the 363
.
.
and so on
the 56th selection is one of 310 left
Answer:
You might be interested in
Hello, there!
The LCM would most likely be:
So, go through all of your factors to find your
of those 
~
The LCM would most likely be:
So, go through all of your factors to find your
~
<span>A(2, -2), B(4, -2), C(1, -3), D(5, -3).
A'(1, 2), B'(1, 4), C'(2, 1), D'(2, 5)
That looks like a rotation 90 degrees around the origin then a translation.
Let's do the rotation ABCD->A"B"C"D"
The rotation is (x,y)->(-y,x)
</span>A"(2, 2), B"(2,4), C"(3,1), D"(3,5).
Compare to
A'(1, 2), B'(1, 4), C'(2, 1), D'(2, 5)
we need to translate one unit to the left.
Answer: 90 degree rotation around the origin then translation by (-1,0)
A'(1, 2), B'(1, 4), C'(2, 1), D'(2, 5)
That looks like a rotation 90 degrees around the origin then a translation.
Let's do the rotation ABCD->A"B"C"D"
The rotation is (x,y)->(-y,x)
</span>A"(2, 2), B"(2,4), C"(3,1), D"(3,5).
Compare to
A'(1, 2), B'(1, 4), C'(2, 1), D'(2, 5)
we need to translate one unit to the left.
Answer: 90 degree rotation around the origin then translation by (-1,0)