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Olegator [25]
4 years ago
9

Select the equations that have the solution m = 19. Mark all that apply. A m − 4 = 15 B 16 = m − 3 C 4 = m − 15 D 3 + m = 23

Mathematics
2 answers:
QveST [7]4 years ago
8 0

Answer:

A, B, C

Step-by-step explanation:

Vanyuwa [196]4 years ago
3 0

Answer:

A, B, C

Step-by-step explanation:

A) m- 4 = 15

Substitute value of m in equation: 19-4 = 15

See if the equation is true: 19-4 is 15 APPLIES

B) 16 = m-3

Substitute: 16 = 19-3

Is it true?: 19 - 3 is 16 APPLIES

C) 4 = m-15

Substitute: 4 = 19 - 15

True?: 19-5 is 4 APPLIES

D) 3 + m = 23

Substitute: 3 + 19 = 23

True?: 3 + 19 is 22 not 23 DOES NOT APPLY

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1: x divided 7. 2: 10 + x. 3: x - 14. 4: 8x
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What is the product of 2x -5 and 3x^2 + 5x - 7? Write your answer in standard form. A. Show your work. B. Is the product of 2x -
VikaD [51]

Answer:

A)What is the product of 2x -5 and 3x^2 + 5x - 7? Write your answer in standard form.

6x³ - 5x² - 39x + 35 = 0

B. Is the product of 2x -5 and 3x^2 + 5x -7 equal to the product of 5x - 2 and 3x^2 + 5x - 7?

No it is not.

Step-by-step explanation:

A)What is the product of 2x -5 and 3x^2 + 5x - 7? Write your answer in standard form.

(2x - 5) (3x² + 5x - 7)

= 2x(3x² + 5x - 7) -5(3x² + 5x - 7)

= 6x³ + 10x² - 14x -15x² - 25x +35

Collecting like terms

= 6x³ +10x² - 15x² - 14x - 25x +35

= 6x³ - 5x² - 39x + 35

In standard form

6x³ - 5x² - 39x + 35 = 0

B. Is the product of 2x -5 and 3x^2 + 5x -7 equal to the product of 5x - 2 and 3x^2 + 5x - 7?

First we find the product of

5x - 2 and 3x² + 5x - 7?

(5x - 2) (3x² + 5x - 7)

5x(3x² + 5x - 7) -2(3x² + 5x - 7)

15x³ + 25x² - 35x - 6x² -10x + 14

Collect like terms

15x³+ 25x² - 6x² -35x - 10x + 14

15x³ + 19x² - 45x + 14 = 0

Hence, the product of 5x - 2 and 3x^2 + 5x - 7

= 15x³ + 19x² - 45x + 14 = 0

The product of 2x -5 and 3x^2 + 5x -7 = 6x³ - 5x² - 39x + 35 = 0

Comparing both products, we can see that

The product of 2x -5 and 3x^2 + 5x -7 ≠ the product of 5x - 2 and 3x^2 + 5x - 7

6 0
3 years ago
Find the value of n (picture provided)
raketka [301]

Answer:

B

Step-by-step explanation:

Absolute value works like this.

For any number you put inside the absolute value bars, it will always come out positive, so -5 and 5 can work.

7 0
3 years ago
1/3ab^2 Solve for a​
Julli [10]

Answer:

a = 18/b²

Step-by-step explanation:

Step 1: Write equation

1/3ab² = 6

Step 2: Solve for <em>a</em>

  1. Multiply both sides by 3: ab² = 18
  2. Divide both sides by b²: a = 18/b²
3 0
4 years ago
7h^9 c^6 / 21^9 c^4 dis hard
almond37 [142]

Step-by-step explanation:

1) Evaluate the exponent

\frac{7h^{9} }{c^{6} }×c^{4}

\frac{7h^{2} c^{6} }{794280046581}×c^{4}

2) Cancel terms that are in both the numerator and denominator

\frac{7h^{9}c^{6}  }{794280046581}×c^{4}

\frac{h^{9}c^{6}  }{113468578083}×c^{4}

3) Combine multiplied terms into a single fraction

\frac{h^{9}c^{6}  }{113468578083}×c^{4}

\frac{h^{9}c^{6}c^{4}   }{113468578083}

4) Combine exponents

\frac{h^{9} c^{6} c^{4} }{113468578083}

\frac{h^{9} c^{6}c^{4}  }{113468578083}

Result ║\frac{h^{9} c^{6}c^{4}  }{113468578083}

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3 years ago
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