Polygons ABCD and A'B'C'D' are shown on the following coordinate grid:A coordinate grid is shown from positive 6 to negative 6 o
n the x-axis and from positive 6 to negative 6 on the y-axis. A polygon ABCD is shown with vertex A on ordered pair 2, negative 2, vertex B on ordered pair 4, negative 2, vertex C on ordered pair 1, negative 3 and vertex D on ordered pair 5, negative 3. A polygon A prime B prime C prime D prime is shown with vertex A prime on ordered pair 1, 2 , vertex B prime on ordered pair 1, 4, vertex C prime on ordered 2, 1 and vertex D prime on ordered pair 2, 5.
What set of transformations is performed on ABCD to form A'B'C'D'?
What set of transformations is performed on ABCD to form A'B'C'D'?
2 answers:
<span>A(2, -2), B(4, -2), C(1, -3), D(5, -3).
A'(1, 2), B'(1, 4), C'(2, 1), D'(2, 5)
That looks like a rotation 90 degrees around the origin then a translation.
Let's do the rotation ABCD->A"B"C"D"
The rotation is (x,y)->(-y,x)
</span>A"(2, 2), B"(2,4), C"(3,1), D"(3,5).
Compare to
A'(1, 2), B'(1, 4), C'(2, 1), D'(2, 5)
we need to translate one unit to the left.
Answer: 90 degree rotation around the origin then translation by (-1,0)
A'(1, 2), B'(1, 4), C'(2, 1), D'(2, 5)
That looks like a rotation 90 degrees around the origin then a translation.
Let's do the rotation ABCD->A"B"C"D"
The rotation is (x,y)->(-y,x)
</span>A"(2, 2), B"(2,4), C"(3,1), D"(3,5).
Compare to
A'(1, 2), B'(1, 4), C'(2, 1), D'(2, 5)
we need to translate one unit to the left.
Answer: 90 degree rotation around the origin then translation by (-1,0)
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First of all, you add 1/3 and 4/5, so you get:
To add 2 fractions, they need to have the same denominator. Since 3 and 5 don't have a common factor, so you multiply 1/3 by 5, and 4/5 by 3, so you get:
Now, the two fractions got the same denominator, and you can add them by adding the numerators over the same denominator. (You don't add denominators in addition) so you get:
That's the sum of 1/3 + 4/5.
Now, they want the sum of the 2 fractions 7 times. So you multiply 17/15 by 7. And as you know, 7 = 7/1. So you get:
In multiplication no need to have the same denominator. You multiply nominators by nominators and denominators by denominators. So you get:
Since 119 and 15 don't have a common factor, so they can't be simplified.
So, the answer is 119/15.
Hope this Helps! :D
To add 2 fractions, they need to have the same denominator. Since 3 and 5 don't have a common factor, so you multiply 1/3 by 5, and 4/5 by 3, so you get:
Now, the two fractions got the same denominator, and you can add them by adding the numerators over the same denominator. (You don't add denominators in addition) so you get:
That's the sum of 1/3 + 4/5.
Now, they want the sum of the 2 fractions 7 times. So you multiply 17/15 by 7. And as you know, 7 = 7/1. So you get:
In multiplication no need to have the same denominator. You multiply nominators by nominators and denominators by denominators. So you get:
Since 119 and 15 don't have a common factor, so they can't be simplified.
So, the answer is 119/15.
Hope this Helps! :D