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3 years ago

5x - y - 4z = -16 x + 3y+ z= 5 2x+ 4y - 3z= 1

Mathematics

1 answer:

Anuta_ua [19.1K]3 years ago

6 0

Answer:

Step-by-step explanation:

hello :

look this solution :

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-6p (p4- 8) what’s the answer ?

Helen [10]

Answer:

-6p^5+48p

Step-by-step explanation:

-6p (p^4- 8)= -6p^5+48p

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3 years ago

Read 2 more answers

NEED ANSWER ASAP PLEASE WILL GIVE BRAINLIEST An integer n is divided by 2 and the quotient is an even integer. What does this te

Nesterboy [21]

Answer:

$n$ is a multiple of 4

Step-by-step explanation:

Let's think about this.

Even numbers are basically numbers that, when divided by 2, get us an integer.

This means that $n$ must be an even integer.

<em>However,</em>

Every other even number, when divided by 2, gets you an odd integer.

This means that every second even number, $n \div 2$ gets us an even number.

This also means that every time $n \div 2$ is an even number, n will be a multiple of 4 (as $2\cdot 2 = 4$ ).

Test this out with any even number that's a multiple of 4 (all multiples of 4 are even numbers)

Hope this helped!

4 0

3 years ago

6.8 . 10^4 standard form

Yuri [45]

The answer would be 68000 you can find it easily by moving the decimal to the right if the exponent is positive if its negative move it to the left.

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4 years ago

Consider a large shipment of 400 refrigerators, of which 40 have defective compressors. If X is the number among 15 randomly sel

Vlad [161]

Answer:

The required probability is 0.94

Step-by-step explanation:

Consider the provided information.

There are 400 refrigerators, of which 40 have defective compressors.

Therefore N = 400 and X = 40

The probability of defective compressors is:

$\frac{40}{400}=0.10$

It is given that If X is the number among 15 randomly selected refrigerators that have defective compressors,

That means n=15

Apply the probability density function.

$P(X=x)=^nC_xp^x(1-p)^{n-x}$

We need to find P(X ≤ 3)

$P(X\leq3) =P(X=0)+P(X=1)+P(X=2)+P(X=3)\\P(X\leq3) =\frac{15!}{15!}(0.1)^0(1-0.1)^{15}+\frac{15!}{14!}(0.1)^1(1-0.1)^{14}+\frac{15!}{13!2!}(0.1)^2(1-0.1)^{13}+\frac{15!}{12!3!}(0.1)^3(1-0.1)^{12}\\$

$P(X\leq3) =0.944444369992\approx 0.94$

Hence, the required probability is 0.94

4 0

3 years ago

The sum of the ages of Berma, her mother Rinna and her father Erwin is 80. Two years from now, Rinna’s age will be 13 less than

jekas [21]

Answer: Berma is 5 years old

Rinna is 38 years old

Erwin is 37 years old

Step-by-step explanation:

Let x represent Berma's age

Let y represent Rinna's age

Let z represent Erwin's age

Since the sum of their ages is 80,

x + y + z = 80 - - - - - - -1

Two years from now, Rinna’s age will be 13 less than the sum of Erwin’s age and twice Berma’s age. This means that

y +2 = [ (z+2) + 2(x+2) ] - 13

y +2 = z + 2 + 2x + 4 - 13

2x - y + z = 13 + 2 - 4 -2

2x - y + z = 9 - - - - - - -2

Three years ago, 15 times Berma’s age was 5 less than the age of Rinna. It means that

15(x - 3) = (y - 3) - 5

15x - 45 = y - 3 - 5

15x - y = - 8 + 45

15x - y = 37 - - - - - - - -3

From equation 3, y = 15x - 37

Substituting y = 15x - 37 into equation 1 and equation 2, it becomes

x + 15x - 37 + z = 80

16x + z = 80 + 37 = 117 - - - - - - 4

2x - 15x + 37 + z = 9

-13x + 2 = -28 - - - - - - - - -5

subtracting equation 5 from equation 4,

29x = 145

x = 145/29 = 5

y = 15x - 37

y = 15×5 -37

y = 38

Substituting x= 5 and y = 38 into equation 1, it becomes

5 + 38 + z = 80

z = 80 - 43

z = 37

6 0

3 years ago