I'm going to separate this into sections so it makes more sense for you to read. For the problems with π where you have to round, ask your teacher where to round, unless your textbook specifies it:
A – 100 cm^2
To calculate area of squares, you multiply l • w. It's a square, so all sides are equal, and since we know that one side = 10 cm, the area is 10 • 10 = 100
B – πr^2 (not sure if the r shows up very well, so I'm retyping it in words - pi • radius squared)
C – 25π cm^2 or an approximate round like 78.54 cm^2 (ask your teacher about this – it could be to the nearest tenth, hundredth, etc.)
To find the area of a circle, you must follow the formula πr^2. In this case, the diameter is 10. The radius is half the diameter, so to substitute the values you must find 10 ÷ 2 = 5. So the radius is 5 cm. From there you can substitute r for 5, ending up with π • 5^2. 5^2 = 25, so the area is 25π, or about 78.54, depending on where the question wants you to round.
D – An approximate round (to the nearest hundredth it is 21.46 cm^2)
To find the area of the shaded region, just subtract the circle's area from the square's area, or 100 – 25π ≈ 21.46. Again, though, ask your teacher about where to round, unless your textbook specifies it.
E – dπ (diameter • pi)
F – 10π cm^2 or an approximate round like 31.42 cm^2
The diameter is 10. 10π ≈ 31.42
Hope this helps!
Do you want square root? And If so then here is the answer:Rewrite <span><span>√37</span>37</span> as <span><span>√3√7</span>37</span>.<span><span>√3√7</span>37</span>Multiply <span><span>√3√7</span>37</span> by <span><span>√7√7</span>77</span>.<span><span><span>√3√7</span><span>√7√7</span></span><span>3777</span></span>Simplify. And in the end of, this I put the decimals.√<span><span>217</span><span>217</span></span>The result can be shown in both exact and decimal forms.Exact Form:<span><span><span>√21</span>7</span></span>Decimal Form:<span>0.65465367<span>… not sure this answer.
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It means <span>θ is in fourth quardant.</span>
Answer:
Step-by-step explanation:
The area of the rectangle is 3x(2x+5)=6x^2 + 15x
The are of the triangle is 2(x-3)/2 = x-3
Now subtract the triangle are from the rectangles area
6x^2 + 15x - x + 3 = 6x^2 + 14x + 3
