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3 years ago

15

Find the value of x

1 answer:

ad-work [718]3 years ago

7 0

Answer:
18

It’s literally 72 divided by 4 which equals 18

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If tanA=a <br>then find sin4A-2sin2A/ sin4A+2sin2A

anygoal [31]

Answer:

The value of the given expression is

$\frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2$

Step by step Explanation:

Given that $tanA=a$

To find the value of $\frac{sin4A-2sin2A}{sin4A+2sin2A}$

Let us find the value of the expression :

$\frac{sin4A-2sin2A}{sin4A+2sin2A}=\frac{2cos2Asin2A-2sin2A}{2cos2Asin2A+2sin2A}$ ( by using the formula $sin2A=2cosAsinA$ here A=2A)

$=\frac{2sin2A(cos2A-1)}{2sin2A(cos2A+1)}$

$=\frac{(cos2A-1)}{(cos2A+1)}$

$=\frac{(-(1-cos2A))}{(1+cos2A)}$ (using $sin^2A+cos^2A=1$ here A=2A)

$=\frac{-(sin^2A+cos^2A-(cos^2A-sin^2A))}{sin^2A+cos^2A+(cos^2A-sin^2A)}$ (using $cos2A=cos^2A-sin^2A$ here A=2A)

$=\frac{-(sin^2A+cos^2A-cos^2A+sin^2A)}{sin^2A+cos^2A+(cos^2A-sin^2A)}$

$=\frac{-(sin^2A+sin^2A)}{cos^2A+cos^2A}$

$=\frac{-2sin^2A}{2cos^2A}$

$=-\frac{sin^2A}{cos^2A}$

$=-tan^2A$ ( using $tanA=\frac{sinA}{cosA}$ here A=2A )

$=-a^2$ (since tanA=a given )

Therefore $\frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2$

6 0

3 years ago

Write the product as a mixed number 5x1 7/8

Naddik [55]

Answer:

10 5/8

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

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antiseptic1488 [7]

The answer to your question is .........

5 0

3 years ago

Sarah claims that when you divide, the number you are dividing always gets smaller. John says this is not true. Who is correct?

inn [45]

Answer:

D

Step-by-step explanation:

John is correct as Dividing does not always gets the quantity smaller for example if we divide 4 by 0.5

We get

4/0.5= 8

6 0

2 years ago

8 dozen cakes equal how many cakes

lord [1]

Answer: 96

Step-by-step explanation: take 12 (1 dozen) and times it by 8

12x8=96

3 0

3 years ago