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3 years ago

5

Find scale factor, value of x, y & z please

1 answer:

zloy xaker [14]3 years ago

3 0

I'm Super Duper Sorry But Unfortunately I Don't Know The Answer I Need Points Because I Have A Timed Test And I Need Answers For My Questions Again I'm Super Sorry I Wish I Could Help But I'm Desperate. : (

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Write an algebraic expression for the phrase.

Nataly [62]

The product of p and 9 mean 9*p so 9p so the 3rd choice is right sure

6 0

3 years ago

Can someone help me with a question!?!?

Len [333]

If the parent graph f(x) = x² is changed to f(x) = 2x², the vertex of the parabola will still remain (0, 0) because whenever the equation of a parabola is in the form y = ax², the vertex will always be (0, 0).

Now if <em>a</em> is a big number, the parabola will become narrower.

So it will stretch vertically and become narrower.

8 0

3 years ago

Which number line shows the solution set for |y-9| <12

RUDIKE [14]

Answer:

Option c

$y\geq-3$ or $y \leq 21$

Step-by-step explanation:

The absolute value is a function that transforms any value x into a positive number.

Therefore, for the function $f(x) = |x|$ x> 0 for all real numbers.

Then the inequation:

$|y-9| \leq 12$ has two cases

$(y-9)$ if $y \geq 9$ (i)

$-(y-9)$ if $y < 9$ (ii)

We solve the case (i)

$y \leq 9 + 12\\y\leq21$

We solve the case (ii)

$-y +9 \leq 12\\-y \leq 12-9\\y \geq -3$

Then the solution is:

$y\geq-3$ or $y \leq 21$

8 0

3 years ago

What is 93756391215 divided by 3

emmasim [6.3K]

31252130405 is the answer :)

7 0

3 years ago

Read 2 more answers

The length of a rectangle is 5959 inches greatergreater than twice the width. if the diagonal is 2 inches more than the length,

lorasvet [3.4K]

Length: 2w + 59

width: w

diagonal: (2w + 59) + 2 = 2w + 61

Length² + width² = diagonal²

(2w + 59)² + (w)² = (2w + 61)²

(4w² + 118w + 3481) + w² = 4w² + 122w + 3721

5w² + 118w + 3481 = 4w² + 122w + 3721

w² + 118w + 3481 = 122w + 3721

w² - 4w + 3481 = 3721

w² - 4w - 240 = 0

a = 1, b = -4, c = -240

w = $[-(b) +/- \sqrt{(b)^{2} - 4(a)(c) }]/2(a)$

= $[-(-4) +/- \sqrt{(-4)^{2} - 4(1)(-240) }]/2(1)$

= $[4 +/- \sqrt{(16 + 960) }]/2$

= $[4 +/- \sqrt{(976) }]/2$

= $[2 +/- 4\sqrt{(61) }]/2$

= $1 +/- 2\sqrt{(61) }$

since width cannot be negative, disregard 1 - 2√61

w = 1 + 2√61 ≈ 16.62

Length: 2w + 59 = 2(1 + 2√61) + 59 = 2 + 4√61 + 59 = 61 + 4√61 ≈ 92.24

Answer: width = 16.62 in, length = 92.24 in

7 0

3 years ago