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kow [346]
3 years ago
8

Georgetown and Franklin are 9.7 in apart on a map that has a scale of 1.1 in : 15 mi. How far apart are the real cities?

Mathematics
1 answer:
lina2011 [118]3 years ago
5 0
\bf \begin{array}{ccllll}
inches&miles\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
1.1&15\\
9.7&x
\end{array}\implies \cfrac{1.1}{9.7}=\cfrac{15}{x}\impliedby \textit{solve for "x"}
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Þolve for x:<br>1 - 5.2<br>= -6<br>3<br>3(x - 2)+5 = 7(x - 3)<br>x + 4<br>2<br>6<br>5<br>3​
Studentka2010 [4]

Answer:

A family of four is going to the amusement park. Tickets normally cost $56.99 per person. The park is offering a deal where a package of four tickets costs $155. How much will the family save if they buy the package deal?

Step-by-step explanation:

4 0
3 years ago
Please answer, I’m struggling allot
agasfer [191]

Answer: -3

Step-by-step explanation:

y2-y1/x2-x1

(1,0)

(0,3)

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4 0
3 years ago
Choose the graph which represents the solution to the inequality. 12x + 4 ≤ -8
user100 [1]

Answer:

<h2>x\leq -1</h2>

Step-by-step explanation:

Steps:

12x+4-4\leq -8

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12x+4-4\leq -8-4

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Divide both sides by 12:

\frac{12x}{12} \leq \frac{-12}{12}

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3 0
3 years ago
If the acceleration of an object is given by dv/dt = −2v, Find the position function s(t) if v(0) = 7 and s(0) = 0.
kirill [66]

Answer:

Step-by-step explanation:

Given that acceleration of an object is

\frac{dv}{dt} =-2v\\\frac{dv}{v} =-2dt\\ln v = -2t+C\\

is the solution to the differential equation

Since v(0) =7

we get ln 7 = C

Hence lnv = -2t+ln 7\\v=7e^{-2t}

since velocity is rate of change of distance s we have

v=\frac{ds}{dt} =7e^{-2t}\\s= [tex]s(t) =\frac{-7}{2} (e^{-2t})+C)[

substitute t=0 and s=0

C=7/2

So solution for distance is

s(t) =\frac{-7}{2} (e^{-2t}-1)

4 0
3 years ago
Which expression shows the result of applying the distributive property to  12(5y+4) ?
brilliants [131]
<span>12(5y+4)
= 12(5y) + 12(4)
= 60y + 48

hope it helps</span>
6 0
3 years ago
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