All categories

3 years ago

Georgetown and Franklin are 9.7 in apart on a map that has a scale of 1.1 in : 15 mi. How far apart are the real cities?

1 answer:

lina2011 [118]3 years ago

5 0

$\bf \begin{array}{ccllll}
inches&miles\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
1.1&15\\
9.7&x
\end{array}\implies \cfrac{1.1}{9.7}=\cfrac{15}{x}\impliedby \textit{solve for "x"}$

You might be interested in

Determine which sequence is an arithmetic sequence.

dlinn [17]

Answer:

A is correct

Step-by-step explanation:

because the sequence is the 4 and 4

-7 + 4= -3

-3 + 4= 1

1 + 4= 5

6 0

3 years ago

If b=5 what is b to the power of 5

Sonja [21]

Answer: 5^5 = 3125

Step-by-step explanation:

To the power of mostly means multiplying it by itself the number of times giving so for your problem it is 5 times itself 5 times so 5*5*5*5*5 = 3125

5 0

3 years ago

Read 2 more answers

Nathan and his brother Zach love to play video games. Right

Monica [59]

Answer:

$N=2Z-11$

$\begin{array}{cc}\text{Zac's score}&\text{Natan's score}\\ 6&1\\7&3\\8&5\\9&7\end{array}$

Step-by-step explanation:

Nathan's score is 11 less than 2 times Zac's score.

Let Z points be Zac's score and N points be Natan's score. then

2 times Zac's score = 2Z

11 less than 2 times Zac's score = 2Z -11

So, N = 2Z - 11

1. If Z=6, then $N=2\cdot 6-11=12-11=1$

2. If Z=7, then $N=2\cdot 7-11=14-11=3$

3. If Z=8, then $N=2\cdot 8-11=16-11=5$

4. If Z=9, then $N=2\cdot 9-11=18-11=7$

Thus, four other possibilities are

$\begin{array}{cc}\text{Zac's score}&\text{Natan's score}\\ 6&1\\7&3\\8&5\\9&7\end{array}$

3 0

3 years ago

Write −2.32 as a mixed number in simplest form.

skelet666 [1.2K]

Answer: -2 8/25

Step-by-step explanation:

-2.32 * 100/100

2.32*100/100

-232/200

Simplest form reduced by:

-58*4/25*4

-58/25

-2 8/25

7 0

3 years ago

Find the distance between the points (4,-2) and (0,10)

vagabundo [1.1K]

We can solve this problem by using the distance formula. The distance formula is: $\sqrt{(x_{1}-x)^{2} + (y_{1} - y)^{2}}$ We can now put in values and solve.

$\sqrt{(4-0)^{2} + (-2-10)^{2}}$

$\sqrt{16 + 144}$

$\sqrt{160}$

3 0

3 years ago