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3 years ago

8

Georgetown and Franklin are 9.7 in apart on a map that has a scale of 1.1 in : 15 mi. How far apart are the real cities?

1 answer:

lina2011 [118]3 years ago

5 0

$\bf \begin{array}{ccllll}
inches&miles\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
1.1&15\\
9.7&x
\end{array}\implies \cfrac{1.1}{9.7}=\cfrac{15}{x}\impliedby \textit{solve for "x"}$

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If k is the midpoint of hj and hk =x+6 and hj =4x-6 then What does kj equal

leva [86]

Given: k= midpoint
hk=x+6
hj=4x-6

Remember midpoint cuts the segment hj in equal parts that means hk=kj and hk+kj=hj
hk+hk=hj
2hk=hj

2hk=hj
2 (x+6)=(4x-6)
2x+12=4x-6
2x-2x+12=4x-2x-6
12=2x-6
12+6=2x-6+6
18=2x
18/2=2x/2
9=x

hk=kj=x+6=(9)+6=15
kj=15

4 0

3 years ago

If 9 is added to twice a number and this sum is multiplied by 6, the result is the same as if the number is multiplied by 5 and

Alexxx [7]

Let's represent that number as X:
6(9+2X) = 5X + 12
54 + 12X = 5X + 12
7X = -42
X = -6

8 0

3 years ago

Complete the table of values for y= x^2-2x-3

Levart [38]

Answer:

x=3,y=0

x=-1,y=0

Step-by-step explanation:

We will have to factorise to get the value of x before solving for y

Let's solve

y=x^2-2x-3

To factorise x

x^2-3x+x-3

x(x-3)+1(x-3)

(x-3)+(x+1)

x-3=0

x=3

x+1=0

x=-1

Let's substitute the value of value to get the value for y

y=x^2-2x-3

When x is 3

y=3^2-2(3)-3

y=9-6-3

y=0

When x is-1

y=(-1)^2-2(-1)-3

y=1+2-3

y=0

Therefore when x is 3,y is 0

When x is -1,y is 0

3 0

4 years ago

Read 2 more answers

Please help will make brainliest. Write the equation of a line that is parallel to y=9 and that passes through the point (3,-8)

kow [346]

Answer:

y= -8

Step-by-step explanation:

$\frac{y- y1}{x- x1} = \frac{y + 8}{x - 3} = m$

where m is the slope of the line.

m= 0 which is equal to the slope of the line y=9

because both are parallel.

$y + 8 = 0(x - 3)$

$= > y = - 8$

4 0

3 years ago

You are resurfacing your backyard pool. The pool is in the shape of a rectangular prism with a length of 20 ft, a width of 10 ft

zepelin [54]

Answer:

$440\ ft^2$

Step-by-step explanation:

we know that

The area of the backyard pool to be resurfaced is equal to the area of the base plus the area of its four lateral sides.

so

$A=B+PH$

where

B is the area of the base

P is the perimeter of the base

H is the depth of the pool

<em>Find the area of the base B</em>

$B=(L)(W)$

substitute the given values

$B=(20)(10)=200\ ft^2$

<em>Find the perimeter of the base P</em>

$P=2(L+W)$

substitute the given values

$P=2(20+10)=60\ ft$

we have

$H=4\ ft$

<em>Find the area of the backyard pool to be resurfaced</em>

$A=B+PH$

substitute the values

$A=200+60(4)$

$A=440\ ft^2$

3 0

3 years ago