Well here are two equivalent different expressions of my making that you could use for this question.
f(x) = 2x - 7
g(x) = 3x - 28 / 2
When x = 7, these two different expressions will equate to the same value of 7. If you meant something else let me know, otherwise this is what you should put for your essay-question.
Let's simplify step-by-step.
2/
5
y−4+7−
9
/10
y
=
2
/5
y+−4+7+
−9
/10
y
Combine Like Terms: =
2
/5
y+−4+7+
−9
/10
y
(2
/5
y+
−9
/10
y)+(−4+7)
=
−1
/2
y+3
Answer: =
−1
/2
y+3
Hope I could help! :)
8x2+6x-2
I think! because 8,6, and 2 are all divisible by 2
and 3. Factor the quadratic
2(4x-1)(x+1)
We have that
the expression 2f + 4f + 2 – 3-------> we can group it (2f+4f)+(2-3)
(2f+4f)+(2-3)=(6f-1)
therefore
the expression [2f + 4f + 2 – 3] is equivalent to [6f-1]
if the expression [6f-1] for f=3 is 17
then
the expression [2f + 4f + 2 – 3] for f=3 is also 17
<span>let's check it
</span>[2*3 + 4*3 + 2 – 3]--------> [6+12+2-3]=[20-3]=17------> is ok
Answer:
A: f(x)=10cos(2π/5 x)+10
Step-by-step explanation:
The coefficient of x in the cosine argument of the function will be 2π/period. Since the period is 5, the coefficient is 2π/5. This observation eliminates choices B and C.
The description "not a reflection of the parent function over the x-axis" means the multiplier of the cosine function is not negative, eliminating choice D.
The remaining choice A matches the description.
