Using proportions, it is found that Ermias is traveling at a rate of 11 mph and Jeremiah at a rate of 19 mph.
<h3>What is a proportion?</h3>
A proportion is a fraction of a total amount, and the measures are related using a rule of three.
Jeremiah travels 8 mph faster than Ermias, hence their velocities are:
x, x + 8
They travel in opposite directions, hence in one hour they are 2x + 8 apart.
In eight hours, the distance is 8(2x + 8), which is of 240 miles, hence:
8(2x +8) = 240
2x + 8 = 30
2x = 22
x = 11.
Then:
- x = 11 + 8 = 19 -> Jeremiah.
More can be learned about proportions at brainly.com/question/24372153
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7.24-4.002=3.238
It is 3.238 meters longer than higher
<span>D. She wrote articles and gave speeches about hate crimes against blacks in the south.</span>
Answer:
The quadratic function whose graph contains these points is 
Step-by-step explanation:
We know that a quadratic function is a function of the form
. The first step is use the 3 points given to write 3 equations to find the values of the constants <em>a</em>,<em>b</em>, and <em>c</em>.
Substitute the points (0,-2), (-5,-17), and (3,-17) into the general form of a quadratic function.



We can solve these system of equations by substitution
- Substitute


- Isolate a for the first equation

- Substitute
into the second equation



The solutions to the system of equations are:
b=-2,a=-1,c=-2
So the quadratic function whose graph contains these points is

As you can corroborate with the graph of this function.
Hello,
Let's place the last digit: it must be 2 or 4 or 8 (3 possibilities)
It remainds 4 digits and the number of permutations fo 4 numbers is 4!=4*3*2*1=24
Thus there are 3*24=72 possibilities.
Answer A
If you do'nt believe run this programm
DIM n(5) AS INTEGER, i1 AS INTEGER, i2 AS INTEGER, i3 AS INTEGER, i4 AS INTEGER, i5 AS INTEGER, nb AS LONG, tot AS LONG
tot = 0
n(1) = 1
n(2) = 2
n(3) = 4
n(4) = 7
n(5) = 8
FOR i1 = 1 TO 5
FOR i2 = 1 TO 5
IF i2 <> i1 THEN
FOR i3 = 1 TO 5
IF i3 <> i2 AND i3 <> i1 THEN
FOR i4 = 1 TO 5
IF i4 <> i3 AND i4 <> i2 AND i4 <> i1 THEN
FOR i5 = 1 TO 5
IF i5 <> i4 AND i5 <> i3 AND i5 <> i2 AND i5 <> i1 THEN
nb = ((((n(i1) * 10) + n(i2)) * 10 + n(i3)) * 10 + n(i4)) * 10 + n(i5)
IF nb MOD 2 = 0 THEN
tot = tot + 1
END IF
END IF
NEXT i5
END IF
NEXT i4
END IF
NEXT i3
END IF
NEXT i2
NEXT i1
PRINT "tot="; tot
END