Answer:
C, 1 : 16
Step-by-step explanation:
Small Circle
The radius is half of the diameter. 3 inches.
π×r²=A
We'll use 3.14 for pi.
3.14×9
28.26 in²
Bigger Circle
6×4= 24
So the diameter is 24. The radius is 12.
3.14×12²
3.14×144
452.16 in²
Let's divide.
452.16÷ 28.26
= 16
Therefore, the answer is C, 1 : 16.
Hope this helps, please mark brainliest if possible :)
Answer:
47. 1 5/8
48. 1 1/12
Step-by-step explanation:
<em>47. </em>
<em>First, convert the denominators to be the same.</em>
8 1/2 minutes, Ruby's mile time, can be converted to 8 4/8.
<em>Then subtract.</em>
8 4/8 - 6 7/8 = 1 5/8
<em>48.</em>
<em>Make sure the denominators are the same. Both denominators can be multiplied by 3 or 4 to become 12.</em>
1 1/4 can be multiplied by 3 to get 1 3/12. And 1 1/3 can be multiplied by 4 to get 2 4/12.
<em>Then subtract.</em>
2 4/12 - 1 1/3 = 1 1/12
Here is your answer
12m-6
REASON:
6(2m-1)
Multiply 6 with both the terms in bracket, we get
6×2m - 6×1
= 12m-6
HOPE IT IS USEFUL
Given parameters;
Let us solve this problem step by step;
Let us represent Simon's money by S
Kande's money by K
- Simon has more money than Kande
S > K
- if Simon gave Kande K20, they would have the same amount;
if Simon gives $20, his money will be S - 20 lesser;
When Kande receives $20, his money will increase to K + 20
S - 20 = K + 20 ------ (i)
- While if Kande gave Simon $22, Simon would then have twice as much as Kande;
if Kande gave Simon $22, his money will be K - 22
Simon's money, S + 22;
S + 22 = 2(K - 22) ------ (ii)
Now we have set up two equations, let us solve;
S - 20 = K + 20 ---- i
S + 22 = 2(K - 22) ; S + 22 = 2K - 44 ---- ii
So, S - 20 = K + 20
S + 22 = 2K - 44
subtract both equations;
-20 - 22 = (k -2k) + 64
-42 = -k + 64
k = 106
Using equation i, let us find S;
S - 20 = K + 20
S - 20 = 106 + 20
S = 106 + 20 + 20 = 146
Therefore, Kande has $106 and Simon has $146
Answer:
y=-5/3x+20
Step-by-step explanation:
Let the equation of the required line be represented as ![\[y=mx+c\]](https://tex.z-dn.net/?f=%5C%5By%3Dmx%2Bc%5C%5D)
This line is perpendicular to the line ![\[y=\frac{3}{5}x+10\]](https://tex.z-dn.net/?f=%5C%5By%3D%5Cfrac%7B3%7D%7B5%7Dx%2B10%5C%5D)
![\[=>m*\frac{3}{5}=-1\]](https://tex.z-dn.net/?f=%5C%5B%3D%3Em%2A%5Cfrac%7B3%7D%7B5%7D%3D-1%5C%5D)
![\[=>m=\frac{-5}{3}\]](https://tex.z-dn.net/?f=%5C%5B%3D%3Em%3D%5Cfrac%7B-5%7D%7B3%7D%5C%5D)
So the equation of the required line becomes ![\[y=\frac{-5}{3}x+c\]](https://tex.z-dn.net/?f=%5C%5By%3D%5Cfrac%7B-5%7D%7B3%7Dx%2Bc%5C%5D)
This line passes through the point (15.-5)
![\[-5=\frac{-5}{3}*15+c\]](https://tex.z-dn.net/?f=%5C%5B-5%3D%5Cfrac%7B-5%7D%7B3%7D%2A15%2Bc%5C%5D)
![\[=>c=20\]](https://tex.z-dn.net/?f=%5C%5B%3D%3Ec%3D20%5C%5D)
So the equation of the required line is ![\[y=\frac{-5}{3}x+20\]](https://tex.z-dn.net/?f=%5C%5By%3D%5Cfrac%7B-5%7D%7B3%7Dx%2B20%5C%5D)
Among the given options, option 4 is the correct one.
